In this case, for this neutralization reaction, it is possible to realize that one the neutralization products is water (pH=7) and the other one is the salt coming up from the cation of the NaOH and the anion of the HI:

$HI(aq)+NaOH(aq)\rightarrow NaI+H_2O$

Moreover, since the solubility of NaI is large in water, we infer it remains aqueous whereas the water is maintained as liquid:

$HI(aq)+NaOH(aq)\rightarrow NaI(aq)+H_2O(l)$

Which is also balanced as the number of atoms of all the elements is the same at both sides.

Best regards!

7 0

3 years ago

How can a flame test identify an unknown element?

Ilya [14]

Answer:

the answer for this question is the option D

6 0

3 years ago

Consider the reaction at 500 ° C 500°C . N 2 ( g ) + 3 H 2 ( g ) − ⇀ ↽ − 2 NH 3 ( g ) K c = 0.061 N2(g)+3H2(g)↽−−⇀2NH3(g)Kc=0.06

Sav [38]

Answer:

Q = 0.061 = Kc

Explanation:

Step 1: Data given

Temperature = 500 °C

Kc=0.061

1.14 mol/L N2

5.52 mol/L H2

3.42 mol/L NH3

Step 2: Calculate Q

Q=[products]/[reactants]=[NH3]²/ [N2][H2]³

If Qc=Kc then the reaction is at equilibrium.

If Qc<Kc then the reaction will shift right to reach equilibrium.

If Qc>Kc then the reaction will shift left to reach equilibrium.

Q = (3.42)² / (1.14 * 5.52³)

Q = 11.6964/191.744

Q = 0.061

Q = Kc the reaction is at equilibrium.

4 0

3 years ago

How many protons are in oxygen's nucleus?

UkoKoshka [18]

There are eight protons in an Oxygen's nucleus.

8 0

4 years ago

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