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kolbaska11 [484]
3 years ago
14

The factor that affects how easy and electron can be removed from an Atom is the

Chemistry
1 answer:
zheka24 [161]3 years ago
3 0
The ionization energy
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“Dry ice” is the solid form of carbon dioxide. Determine the number of mass of CO2 gas in grams that are present in 61.8 L of CO
Fofino [41]

Answer:

Mass  = 121 g

Explanation:

Given data:

Mass in gram of CO₂ = ?

Volume = 61.8 L

Pressure = standard = 1 atm

Temperature = 273.15 K

Solution:

Formula:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

1 atm × 61.8 L = n ×0.0821 atm.L/ mol.K   × 273.15 k

61.8 L.atm = 22.42 atm.L/ mol × n

n = 61.8 L.atm /22.42 atm.L/ mol

n = 2.76 mol

Mass in gram:

Mass =  number of moles × molar mass

Mass = 2.76 mol × 44 g/mol

Mass  = 121 g

6 0
2 years ago
Vapor pressure can be described as: A) the temperature at which bubbles of vapor appear in a liquid. B) the pressure exerted on
Vanyuwa [196]

Answer: Option (D) is the correct answer.

Explanation:

Vapor pressure is defined as the pressure exerted by the vapors which are present on the surface of a liquid.

For example, vapor pressure of water at room temperature is 0.0313 atm.

On the other hand, the temperature at which the vapor pressure of a liquid equals atmospheric pressure is known as boiling point.

For example, boiling point of water at room temperature is 100^{o}C.

Thus, we can conclude that vapor pressure can be described as the pressure exerted by a gas above the surface of its liquid.

4 0
3 years ago
How many moles are in 2.0 grams of Na?
lisov135 [29]

Answer:

46

Explanation:

Sodium metal has a molar mass of  

22.99

3 0
3 years ago
Please help me I would really appreciate it
denis-greek [22]
The number of students is your independent variable
6 0
3 years ago
A sample of the chiral molecule limonene is 62% enantiopure. what percentage of each enantiomer is present? what is the percent
ikadub [295]

The mixture contains 62 % one isomer and 38 % the enantiomer.

Let’s say that the mixture contains 62 % of the (<em>R</em>)-isomer.

Then % (<em>S</em>) = 100 % -62 % = 38 %

ee = %  (<em>R</em>) - % (<em>S</em>) = 62 % -38 % = 24 %


6 0
3 years ago
Read 2 more answers
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