Answer: 81 people
Step-by-step explanation:
Number of people that attended fair on Saturday = 6737
Number of people that got free admission = 6737/188 = 35.8.
Free admission on Saturday = 35
Number of people that attended fair on Saturday = 8669
Number of people that got free admission = 8669/188 = 46.1
Free admission on Sunday = 46
The people who received a free admission over the two days will be:
= 35 + 46
= 81 people
5.30158730159 is the answer
The equation y represent a proportional relationship because (d) Yes, because its graph is a line that passes through the origin
<h3>How to determine the true statement?</h3>
The equation is given as:
y = x/2
Proportional relationships are represented as:
y = mx
This means that
m = 1/2
Hence, the equation y represent a proportional relationship because (d) Yes, because its graph is a line that passes through the origin
Read more about proportional relationship at
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Answer: 33c12
Step-by-step explanation:
Answer:
![m\angle QSN=65^\circ](https://tex.z-dn.net/?f=m%5Cangle%20QSN%3D65%5E%5Ccirc)
Step-by-step explanation:
In the given figure, PQRS is a rhombus and SRM is an equilateral triangle.
We are also given that SN⊥RM and that ∠PRS = 55°.
And we want to find the measure of ∠QSN.
Remember that since PQRS is a rhombus, the angles formed by its diagonals are right angles. Let the intersection point of the diagonals be K. Therefore:
![m\angle RKS=90^\circ](https://tex.z-dn.net/?f=m%5Cangle%20RKS%3D90%5E%5Ccirc)
Now, RKS is also a triangle. The interior angles of all triangles must be 180. Thus:
![m\angle RKS+m\angle KSR+m\angle SRK=180](https://tex.z-dn.net/?f=m%5Cangle%20RKS%2Bm%5Cangle%20KSR%2Bm%5Cangle%20SRK%3D180)
Substitute in known values:
![90+55+m\angle KSR=180](https://tex.z-dn.net/?f=90%2B55%2Bm%5Cangle%20KSR%3D180)
Solve for ∠KSR:
![m\angle KSR+145=180\Rightarrow m\angle KSR=35^\circ](https://tex.z-dn.net/?f=m%5Cangle%20KSR%2B145%3D180%5CRightarrow%20m%5Cangle%20KSR%3D35%5E%5Ccirc)
Since SRM is an equilateral triangle, this means that:
![m\angle SRM=m\angle RMS=m\angle MSR=60^\circ](https://tex.z-dn.net/?f=m%5Cangle%20SRM%3Dm%5Cangle%20RMS%3Dm%5Cangle%20MSR%3D60%5E%5Ccirc)
Note that RNS is also a triangle. Therefore:
![m\angle SRM+m\angle RNS+m\angle NSR=180](https://tex.z-dn.net/?f=m%5Cangle%20SRM%2Bm%5Cangle%20RNS%2Bm%5Cangle%20NSR%3D180)
Substitute in known values:
![60+90+m\angle NSR=180](https://tex.z-dn.net/?f=60%2B90%2Bm%5Cangle%20NSR%3D180)
So:
![m\angle NSR+150=180\Rightarrow m\angle NSR=30^\circ](https://tex.z-dn.net/?f=m%5Cangle%20NSR%2B150%3D180%5CRightarrow%20m%5Cangle%20NSR%3D30%5E%5Ccirc)
∠QSN is the addition of the two angles:
![m\angle QSN=m\angle KSR+m\angle NSR](https://tex.z-dn.net/?f=m%5Cangle%20QSN%3Dm%5Cangle%20KSR%2Bm%5Cangle%20NSR)
Therefore:
![m\angle QSN=35+30=65^\circ](https://tex.z-dn.net/?f=m%5Cangle%20QSN%3D35%2B30%3D65%5E%5Ccirc)