vi is going in the positive direction (up). (That's my choice). a (acceleration) is going in the minus direction (down). The directions could be reversed.
Givens
vi = 160 ft/s
vf = 0 (the rocket stops at the maximum height.)
a = - 9.81 m/s
t = ????
Remark
YOu have 4 parameters between the givens and what you want to solve. Only 1 equation will relate those 4. Always always list your givens with these problems so you can pick the right equation.
Equation
a = (vf - vi)/t
Solve
- 32 = (0 - 160)/t Multiply both sides by t
-32 * t = - 160 Divide by -32
t = - 160/-32
t = 5
You will also need to solve for the height to answer part B
t = 5
vi = 160 m/s
a = - 32
d = ???
d = vi*t + 1/2 a t^2
d = 160*5 + 1/2 * - 32 * 5^2
d = 800 - 400
d = 400 feet
Part B
You are at the maximum height. vi is 0 this time because you are starting to descend.
vi = 0
a = 32 m/s^2
d = 400 feet
t = ??
formula
d = vi*t + 1/2 a t^2
400 = 0 + 1/2 * 32 * t^2
400 = 16 * t^2
400/16 = t^2
t^2 = 25
t = 5 sec
The free fall takes the same amount of time to come down as it did to go up. Sort of an amazing result.
Answer:
C. 176.6 Square feet (I think)
Step-by-step explanation:
I tried many different ways and got three of the answers above but I think this is the right one.
The equation to find area of a circular cone base: 
- We are given the diameter (15 Feet) but we need to find the radius. So we use the diameter to radius formula:

- Plug in numbers:
≈ 
- Use the Area formula now that you have radius:

- Solve and get =

- Looking at the options the closest one to our answer (off by one-tenth) is C.
Sorry if you get this wrong. I tried lol.
The y-intercept of the trend line is (0,28). The slope of this line is
28-0
m = --------- = 2
14-0
Thus, the equation of the trend line, in variables K and J, is
K = 2J + 28
Answer:
B: $18.40
Step-by-step explanation:
100% is equal to $16 so 5% would be 16/20 or $0.80 then to get 15% you would multiply $0.80 by 3 which is $2.40. This is the tip. Then do $16 + $2.40 and the total + tip is $18.40. (Double check to make sure I'm correct)