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Alex787 [66]
3 years ago
10

Can you answer the bottom problem please

Mathematics
1 answer:
Minchanka [31]3 years ago
7 0

This is not the answer, but I want to tell you that I can't see what the problem says. I would help you, but I can't.

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What is 2x +2 when x =O
almond37 [142]

Answer:

2

Step-by-step explanation:

2 x 0= 0 + 2 = 2

8 0
3 years ago
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Spencer and his sister watched a cartoon movie that was 1 hour and 20 minutes long. After the movie, they played a card game for
liberstina [14]

Answer:

10:45 - they started watching the film at this time

Step-by-step explanation:

4 0
2 years ago
Which function is shown in the graph below ?
Norma-Jean [14]

Answer:

The answer is the second choice.

y=2^x+2 + 2

5 0
3 years ago
Which of the following are true statements.
Mariulka [41]

Answer:

Second statement is true.

The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

Step-by-step explanation:

for first part of statement

The lengths 7, 40 and 41 can not be sides of a right triangle.

If the square of long side is equal to the sum of square of other two sides

then the given length can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

c^{2} =a^{2} +b^{2}----------(1)

Let c=41 and a = 7 and b=40

Put all the value in equation 1.

41^{2} =7^{2} +40^{2}

1681=49+1600

1681=1649

Therefore, the square of long side is not equal to the sum of square of other two sides, So given lengths 7, 40 and 41 can not be sides of a right triangle.

for second part of statement.

The lengths 12, 16, and 20 can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

Let c=20 and a = 12 and b=16

20^{2} =12^{2} +16^{2}

400=144+256

400=400

Therefore, the square of long side is equal to the sum of square of other two sides, So given the lengths 12, 16, and 20 can be sides of a right triangle.

Therefore, The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

8 0
2 years ago
The midpoint of UV is (5, -10). The coordinates of one endpoint are U(3,6). Find the coordinates of endpoint V.
Grace [21]

The answer is (7, -26) for The second endpoint.  

We'll call the midpoint M. In order to find this, we must first note that to find a midpoint we need to take the average of the endpoints. To do this we add them together and then divide by 2. So, using that, we can write a formula and solve for each part of the k coordinates. We'll start with just x values.

(Ux + Vx)/2 = Mx

(Vx + 3)/2 = 5

Vx + 3 = 10

Vx = 7

And now we do the same thing for y values

(Uy + Vy)/2 = My

(Vy + 6)/2 = -10

Vy + 6 = -20

Vy = -26

This gives us the final point of (7, -26)

6 0
2 years ago
Read 2 more answers
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