3 years ago

I NEED HELP URGENT!! what is 20x^3+4x^2-45x-9

1 answer:

5 0

<h3>I'll teach you how to solve 20x^3+4x^2-45x-9</h3>

------------------------------------------------------------------

20x^3+4x^2-45x-9

Add parentheses:

(20x^3+4x^2) + (-45x-9)

Factor out -9 and 4x^2:

-9(5x+1)+4x^2(5x+1)

Factor out the common term 5x+1:

(5x+1)(4x^2-9)

Factor 4x^2- 9:

(5x+1)(2x+3)(2x-3)

Your Answer Is (5x+1)(2x+3)(2x-3)

plz mark me as brainliest :)

You might be interested in

FrozenT [24]

Answer:

d = 1

Step-by-step explanation:

$d\pi = C$

So I would think d = 1

Because pi = 3.14

so...

1(3.14) = C

I'm not 100% but that's what I would say.

Hope this helps!!

3 0

3 years ago

Igoryamba

Answer:

D. 120

Step-by-step explanation:

4 0

3 years ago

Colt1911 [192]

Hello!

√28x³y³ is equal to $2xy\sqrt{7xy}$

We can find this solution through the following steps.

Rewriting the equation by factoring 4 from 28, factoring out x², and factoring out y²
We then can rewrite 4 as 2² in our equation, leaving us with $\sqrt{2^{2}*7*(x^{2}x)*y^{2}y }$
We will then move our x and 7, and rewrite $2^{2}*x^{2}* y^{2}$ as $(2xy)^{2}$
We can then pull the terms from the radical leaving us with $2xy\sqrt{7xy}$