Question

The energy from radiation can be used to cause the rupture of chemical bonds. A minimum energy of 242 kJ/mol is required to break the chlorine–chlorine bond in Cl2. Determine the longest wavelength of radiation that possesses the energy to break the bond.

Answer 1

The question ask to determine the longest wavelength of radiation that possesses the energy to break the bond and the minimum energy of 242kj/mol is required to break the chlorine-chlorine bond so the energy would be that the minimum wave length is 495nm and the high wavelength to it is the color green end of its wave

Answer 2

Answer:

The longest wavelength of radiation is 494.6 nm that will possess the energy to break the bond.

Explanation:

Energy required to break 1 mol of Cl-Cl bond = 242 kJ =242000 J

1kJ = 1000 J

1 mol = $6.022\times 10^{23}$ atoms/particles/ molecules

Energy required to break 1 of Cl-Cl bond = E

$E=\frac{242000 J}{6.022\times 10^{23}}=4.0186\times 10^{-19} J$

Wave length of the radiation with energy E.

$E=\frac{hc}{\lambda }$

h = Planck's constant

c = speed of the light

$\lambda = \frac{6.626\times 10^{-34} J s\times 3\times 10^8 m/s}{4.0186\times 10^{-19} J}$

$\lambda = 4.946\times 10^{-7} =494.6 nm$

The longest wavelength of radiation is 494.6 nm that will possess the energy to break the bond.