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Morgarella [4.7K]
2 years ago
5

Describe Covalent bond.​

Chemistry
1 answer:
melomori [17]2 years ago
3 0

Answer:

<u>Covalent Bond:</u>

The bond formed by the sharing of electron pairs between atoms is called a covalent bond.

<u>For example:</u>

The bonds between H₂O are covalent bonds as they are formed as a result of sharing of electrons.

<u>Types:</u>

There are 5 types of covalent bond:

1) Single covalent bond

2) Double covalent bond

3) Triple covalent bond

4) Polar covalent bond

5) Non-polar covalent bond

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>

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How does amplitude affect the wavelength?<br>​
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Answer:

Amplitude does not effect the wavelength in linear system.

Explanation:

Amplitude:

It is the measure of height from peak to trough.

Wavelength:

It is measure of length from peak to peak.

There is no relation between the amplitude and wavelength but if the system will no more linear then high amplitude can cause the distortion in wave if more frequencies are present. However frequency and wavelength can be related. The wave with higher frequency have shorter wavelength and vise versa.

Frequency:

It is the number of waves passing through a given point in a given time period. It is measure in Hz or s⁻¹

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3 years ago
A student dissolves of urea in of a solvent with a density of . The student notices that the volume of the solvent does not chan
Dimas [21]

The question incomplete , the complete question is:

A student dissolves of 18.0 g urea in 200.0 mL of a solvent with a density of 0.95 g/mL . The student notices that the volume of the solvent does not change when the urea dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to significant digits.

Answer:

The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.

Explanation:

Moles of urea = \frac{18.0 g}{60 g/mol}=0.3 mol

Volume of the solution = 200.0 mL = 0.2 L (1 mL = 0.001 L)

Molarity(M)=\frac{\text{Moles of compound}}{\text{Volume of solution in L}}

Molarity of the urea solution ;

M=\frac{0.3 mol}{0.200 L}=1.50 M

Mass of solvent = m

Volume of solvent = V = 200.0 mL

Density of the urea = d = 0.95 g/mL

m=d\times V=0.95 g/mL\times 200.0 mL=190 g

m = 190 g = 190 \times 0.001 kg = 0.19 kg

(1 g = 0.001 kg)

Molality of the urea solution ;

Molality(m)=\frac{\text{Moles of compound}}{\text{Mass of solvent in kg}}

m=\frac{0.3 mol}{0.19 kg}=1.58 m

The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.

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2 years ago
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3 years ago
Use this chemical equation to answer the following questions: Cl + O3 ➞ ClO + O2
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Explanation:

1. Elements are substances made of the same kind of atoms, unlike compounds that are combination for different kinds of atoms. The elements in the reaction therefore are;

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