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3 years ago

Refer to the following illustration. How many hydrogen atoms could bond with oxygen?

Chemistry

2 answers:

WITCHER [35]3 years ago

4 0

2.

The reason why is because there are 2 available electron spots on the orbital for the oxygen atom. Hydrogen atoms have one proton and one electron, thus, in order to fill the oxygen atom orbital to a full outer shell, a maximum of 2 atoms could bond with the oxygen atoms.

6 electrons (oxygen)+ 1 electron (hydrogen)+ 1 electron (hydrogen)= 8

kiruha [24]3 years ago

3 0

Answer: The number of hydrogen atoms that can combine to oxygen are 2.

Explanation:

Oxygen is the 8th element of the periodic table with electronic configuration: $1s^22s^22p^4$

This element requires 2 electrons to attain stable electronic configuration.

Hydrogen is the 1st element of the periodic table with electronic configuration: $1s^1$

This element will loose 1 electron to attain stable electronic configuration.

2 Hydrogen atoms will share their 1 electron each with 1 oxygen atom. So, that both the element attain stable electronic configuration.

They will form a covalent compound with chemical formula $H_2O$

Hence, the number of hydrogen atoms that can combine to oxygen are 2.

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Consider the electrolysis of molten barium chloride (bacl2). write the half-reactions. include the states of each species.

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Molten barium chloride is separeted into two species :
BaCl₂(l) → Ba(l) + Cl₂(g),
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3 years ago

Britney added 0.05 moles of copper(II) nitrate solution to 0.1 moles of sodium hydroxide solution and

Rama09 [41]

The percent yield of copper hydroxide is 84%

<h3>Stoichiometry</h3>

From the question, we are to determine the percent yield of copper hydroxide

First, we will determine the theoretical mass

From the given balanced chemical equation, we have

Cu(NO₃)₂ + 2NaOH -- Cu(OH)₂ + 2NaNO₃

This means,

1 mole of copper(II) nitrate reacts with 2 moles of sodium hydroxide to produce 1 mole of copper hydroxide

Therefore,
0.05 mole of copper(II) nitrate reacts with 0.1 mole of sodium hydroxide to produce 0.05 mole of copper hydroxide

The theoretical number of moles of copper hydroxide that is produced is 0.05 mole

Now, for the theoretical mass

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of copper hydroxide = 97.56 g/mol

Then,

Theoretical mass = 0.05 × 97.56

Theoretical mass of copper of hydroxide produced is = 4.878 g

Now, for the percent yield of copper hydroxide

Percent yield is given by the formula,

$Percent\ yield = \frac{Actual\ yield}{Theoretical\ yield} \times 100\%$

Then,

$Percent\ yield\ of\ copper\ hydroxide= \frac{4.1}{4.878}\times 100\%$

$Percent\ yield\ of\ copper\ hydroxide= 84\%$

Hence, the percent yield of copper hydroxide is 84%.

Learn more on Stoichiometry here: brainly.com/question/9372758

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