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Whitepunk [10]
2 years ago
13

Refer to the following illustration. How many hydrogen atoms could bond with oxygen?

Chemistry
2 answers:
WITCHER [35]2 years ago
4 0
2. 

The reason why is because there are 2 available electron spots on the orbital for the oxygen atom. Hydrogen atoms have one proton and one electron, thus, in order to fill the oxygen atom orbital to a full outer shell, a maximum of 2 atoms could bond with the oxygen atoms. 

6 electrons (oxygen)+ 1 electron (hydrogen)+ 1 electron (hydrogen)= 8 
kiruha [24]2 years ago
3 0

<u>Answer:</u> The number of hydrogen atoms that can combine to oxygen are 2.

<u>Explanation:</u>

Oxygen is the 8th element of the periodic table with electronic configuration: 1s^22s^22p^4

This element requires 2 electrons to attain stable electronic configuration.

Hydrogen is the 1st element of the periodic table with electronic configuration: 1s^1

This element will loose 1 electron to attain stable electronic configuration.

2 Hydrogen atoms will share their 1 electron each with 1 oxygen atom. So, that both the element attain stable electronic configuration.

They will form a covalent compound with chemical formula H_2O

Hence, the number of hydrogen atoms that can combine to oxygen are 2.

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A group of students created a model showing a type of matter which of the following discribes what is shows by the model?
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Answer:

liquid

Explanation:

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3 years ago
What would the products be for the reaction between Na3PO4 + MgSO4?
ivann1987 [24]

MgSO4 + Na3PO4 = Na2SO4 + Mg3(PO4)2

Answer: The products of Na3PO4 + MgSO4 are Na2SO4 + Mg3(PO4)2

Explanation:

7 0
2 years ago
Help me I got stuck<br> Pls
Sophie [7]
The answer is C because the weight is going down so they form a gas.
3 0
3 years ago
Pu is a nuclear waste byproduct with a half-life of 24,000 y. What fraction of the 239Pu present today will be present in 1000 y
olya-2409 [2.1K]

Answer:

0.9715 Fraction of Pu-239 will be remain after 1000 years.

Explanation:

\lambda =\frac{0.693}{t_{\frac{1}{2}}}

A=A_o\times e^{-\lambda t}

Where:

\lambda= decay constant

A_o =concentration left after time t

t_{\frac{1}{2}} = Half life of the sample

Half life of Pu-239 = t_{\frac{1}{2}}=24,000 y[

\lambda =\frac{0.693}{24,000 y}=2.8875\times 10^{-5} y^{-1]

Let us say amount present of  Pu-239 today = A_o=x

A = ?

A=x\times e^{-2.8875\times 10^{-5} y^{-1]\times 1000 y}

A=0.9715\times x

\frac{A}{A_0}=\frac{A}{x}=0.9715

0.9715 Fraction of Pu-239 will be remain after 1000 years.

7 0
3 years ago
Consider a hypothetical reaction in which A and B are reactants, and C and D are products. If 26 grams of A completely reacts wi
natali 33 [55]

Answer:

The answer to your question is: 24 grams of D

Explanation:

To answer this question we need to remember the Lavoisier law of conservation of mass, which says that in a chemical reaction matter is neither created nor destroyed.

This means that the amount of matter stays the same.

Then, the reaction is

                    A      +      B      ⇒       C      +      D

                 26 g         12 g             14 g            x

mass                              

of reactants      38 g                              ?          mass of products, but it must be

                                                                          equal to the mass of products

Then                14g + x = 38

                        x = 38 - 14

                        x = 24 g of D                                                        

4 0
3 years ago
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