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Whitepunk [10]
3 years ago
13

Refer to the following illustration. How many hydrogen atoms could bond with oxygen?

Chemistry
2 answers:
WITCHER [35]3 years ago
4 0
2. 

The reason why is because there are 2 available electron spots on the orbital for the oxygen atom. Hydrogen atoms have one proton and one electron, thus, in order to fill the oxygen atom orbital to a full outer shell, a maximum of 2 atoms could bond with the oxygen atoms. 

6 electrons (oxygen)+ 1 electron (hydrogen)+ 1 electron (hydrogen)= 8 
kiruha [24]3 years ago
3 0

<u>Answer:</u> The number of hydrogen atoms that can combine to oxygen are 2.

<u>Explanation:</u>

Oxygen is the 8th element of the periodic table with electronic configuration: 1s^22s^22p^4

This element requires 2 electrons to attain stable electronic configuration.

Hydrogen is the 1st element of the periodic table with electronic configuration: 1s^1

This element will loose 1 electron to attain stable electronic configuration.

2 Hydrogen atoms will share their 1 electron each with 1 oxygen atom. So, that both the element attain stable electronic configuration.

They will form a covalent compound with chemical formula H_2O

Hence, the number of hydrogen atoms that can combine to oxygen are 2.

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2 years ago
Using henry's law, calculate the molar concentration of o2 in the surface water of a mountain lake saturated with air at 20 ∘c a
s2008m [1.1K]

Answer: The molar concentration of oxygen gas in water is 1.43\times 10^{-7} mol/L.

Explanation:

Partial pressure of the O_2gas = 685 torr = 0.8905 bar

1 torr = 0.0013 bar

According Henry's law:

p_{o_2}=K_H\times\chi_{O_2}

Value of Henry's constant of oxygen gas at 20 °C in water = 34860 bar

0.0013=34860 bar\times \chi_{O_2}

\chi_{O_2}=\frac{0.8905 bar}{34680 bar}=2.56\times 10^{-5}

Let the number of moles of O_2 gas in 1 liter water be n.

1 Liter water = 1000 g of water

Moles of water in 1 L n_w=\frac{1000 g}{18 g/mol}=55.55 mol

\chi_{O_2}=\frac{n}{n+n_w}

2.56\times 10^{-5}=\frac{n}{n+55.55}

n=1.43\times 10^{-7} moles

Molarity=\frac{\text{Moles of}O_2}{Volume}

Molar concentration of oxygen gas in 1 L of water:

=\frac{1.43\times 10^{-7} moles}{1 L}=1.43\times 10^{-7} mol/L

The molar concentration of oxygen gas in water is 1.43\times 10^{-7} mol/L.

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3 years ago
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