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3 years ago

Help plz I will giv brainliest if it's right

Mathematics

1 answer:

hjlf3 years ago

6 0

Answer:

What does it say.

I can't see the photo at all !

Step-by-step explanation:

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ki77a [65]

Answer:

4lb and 6oz

Step-by-step explanation:

number one is

8 0

3 years ago

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How do I solve this

Afina-wow [57]

Use calculating software for the quickest answer. The answer would be yes with a rate of increase of 1.75

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3 years ago

Joe is trying to solve the equation for x

Stella [2.4K]

D add 7 your trying to get the variable.

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2 years ago

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The following chart shows the number of concert tickets sold and the profit earned. What is the slope of the line through these

Black_prince [1.1K]

Answer:

C.) 4

Step-by-step explanation:

y2 - y1/x2 - x1

m = 160 - 80/60 - 40

m = 80/20

m = 8/2

m = 4/1

m = 4

8 0

2 years ago

(cot^2x - 1)/(csc^2x) = cos2x

Alex787 [66]

Answer:

Step-by-step explanation:

The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):

$cos(2x)=cos^2x-sin^2x$ ,

$cos(2x)=1-2sin^2x$ , and

$cos(2x)=2cos^2x-1$

We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants. Rewriting gives you:

$\frac{\frac{cos^2x}{sin^2x} -\frac{sin^2x}{sin^2x} }{\frac{1}{sin^2x} }$

Notice I also wrote the 1 in terms of sin^2(x).

Now we will put the numerator of the bigger fraction over the common denominator:

$\frac{\frac{cos^2x-sin^2x}{sin^2x} }{\frac{1}{sin^2x} }$

The rule is bring up the lower fraction and flip it to multiply, so that will give us:

$\frac{cos^2x-sin^2x}{sin^2x} *\frac{sin^2x}{1}$

And canceling out the sin^2 x leaves us with just

$cos^2x-sin^2x$ which is one of our identities.

5 0

3 years ago