For this case we have the following equation:
w = || F || • || PQ || costheta
Where,
|| F ||: force vector module
|| PQ ||: distance module
costheta: cosine of the angle between the force vector and the distance vector.
Substituting values:
w = (60) * (100) * (cos (45))
w = 4242.640687 lb.ft
Answer:
The work done pushing the lawn mower is:
w = 4242.640687 lb.ft
Answer:
First find the hypotenuse of the small triangle then use that value as the base of the upper triangle. Evaluate the equation formed with the “x"
Answer: So lets say that the width is w. The length(L) is 4 meters greater than 3 times the width. 3 times the width would be 3w, and then 4 meters greater than that would be 3w+4. You have two widths and two lengths to a rectangle that must add up to equal 72. So 2w + 2L =72. But remember that one L equals 3w+4
2(w) + 2(3w+4) = 72
2w+6w+8=72
8w+8=72
8w=64
w=8
L=3w+4
L=3(8)+4
L=24+4
L=28
So the dimensions are 8 meters by 28 meters
To check 2(8)+2(28)=72
He can make a 70 or higher to keep a B avg.
