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Svetach [21]
3 years ago
15

To hide their loot, thieves put the 1.20 kg gold that they had robbed into a small box and threw it in a lake. The mass of the e

mpty box was 400 grams, and the dimension 12cm3 . When the box is closed with the gold inside it, it is well seated so that water dont enter it. To their surprise, the box floated on the water. Calculate the distance from the bottom of the box to the water level (i.e. how many cm is it inside the water?)
Density: water = 1 g/cm3 = 100 kg/m3 ----------- Gold = 19.3 g/cm3 19,300 kg/m3
Physics
1 answer:
Dmitry [639]3 years ago
3 0

Answer:

11.1 cm

Explanation:

Let d be the depth upto which box dipped into water.

Volume of water displaced

.12\times .12\times d m^3\\

=.0144d

Weight of water displaced = upthrust

=.0144d\times 10^3\times g\\    [ density of water is 1000kg /m³]

=14.4dg This will act upwards.

Total downward force = 1.2 +.4 = 1.6 g

For equilibrium

1.6g = 14.4 gd

d = .111 m

=11.1 cm.

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Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelen
Marta_Voda [28]

Answer:

a) that laser 1 has the first interference closer to the central maximum

c) Δy = 0.64 m

Explanation:

The interference phenomenon is described by the expression

         d sin θ = m λ

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For the separation of the lines we use trigonometry

        tan θ = sin θ / cos θ = y / x

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          tan θ = sin θ = y / x

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a) and b) We apply the equation to the first laser

          λ = d / 20

          d y / x = m d / 20

          y = m x / 20

          y = 1 4.80 / 20

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The second laser

        λ = d / 15

          d y / x = m d / 15

          y = m x / 15

          y = 0.32 m

We can see that laser 1 has the first interference closer to the central maximum

c) laser 1

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            y₂ = 0.48 m

For laser 2 they ask us for the third minimum m = 3

In this case to have a minimum we must add half wavelength

         y₃ = (m + ½) x / 15

         m = 3

         y₃ = (3 + ½) 4.8 / 15

         y₃ = 1.12 m

        Δy = 1.12 - 0.48

        Δy = 0.64 m

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