Uncertainty in 21.0 C is<br> A. 0.1<br> B. 0.2<br> C. 0.05

A container of water is lifted vertically 3.0 m then returned to its original position. If the total weight is 30 N, how much wo

mariarad [96]

Answer:

Work done, W = 0

Explanation:

Given that, a container of water is lifted vertically 3.0 m then returned to its original position.The total weight of the container is 30 N. We need to find the total work done by the container. We know that the work done by an object is given by :

W = F × d

Where

F is the applied force

d is the displacement of the object

It is mentioned that the container returns to its original position, the displacement of the container is equal to 0. Hence, no work was done by the container of water.

3 0

3 years ago

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Two positive point charges, each of which has a charge of 2.5 × 10−9 C, are located at y = + 0.50m and y = − 0.50m. Find the mag

Salsk061 [2.6K]

Answer:

The resultant electric force is 14.8N to the right.

Explanation:

Since the three charges aren't in the same line, we have to break down the force in components. First, we need to know the distance from the third charge to the other ones. That is made using the Pythagorean Theorem. As the figure is symmetric with respect to the x-axis, the two distances are the same:

$r=\sqrt{(0.50m)^{2}+(0.70m)^{2}}=0.86m$

Now, we use the Coulomb's Law to obtain the magnitude of the individual forces caused by each charge on the third charge:

$|F_{13}|=k\frac{q_1q_3}{r^{2}} \\\\|F_{13}|=(9*10^{9}Nm^{2}/C^{2})\frac{(2.5*10^{-9}C)(3.0*10^{-9}C)}{(0.86m)^{2}}\\\\|F_{13}|=9.1N$

For the same reason the distances are the same, the magnitude of the forces are the same:

$|F_{23}|=|F_{13}|=9.1N$

So, to get the resultant force, we have to break down this forces in components. To do this, we need their angles with respect to the x-axis. Let θ₁ and θ₂ be these angles, respectively. Then, we calculate them using trigonometry:

$\theta_1=\arctan(\frac{-0.50m}{0.70m})=-35.5\°\\\\\theta_2=\arctan(\frac{0.50m}{0.70m})=35.5\°$

Now, we calculate the components of the forces:

$F_{13}_x=F_{13}\cos\theta_1=9.1N\cos(-35.5\°)=7.4N\\\\F_{13}_y=F_{13}\sin\theta_1=9.1N\sin(-35.5\°)=-5.3N\\\\F_{23}_x=F_{23}\cos\theta_2=9.1N\cos(35.5\°)=7.4N\\\\F_{23}_y=F_{23}\sin\theta_2=9.1N\sin(35.5\°)=5.3N$

Evidently, the y-components cancel out, and the resultant electric force on the third charge is $7.4N+7.4N=14.8N$ along the x-axis (to the right, because it's positive).

8 0

3 years ago

How do protons and electrons differ in their electric charge

Daniel [21]

Answer:proton is positively charged and electron is negatively charged

Explanation: electrical forces depend on the property of matter called electric charge. The charge of protons and electrons are exactly the same size but the proton is positively charged while the electron is negatively charged

7 0

3 years ago

A certain car going from Atlanta to Philadelphia averages 24.0 m/s over the course of the trip. Determine how long it takes the

Dennis_Churaev [7]

Answer:

14.5 hours

Explanation:

The relationship between speed, time and distance for a uniform motion is

$v=\frac{d}{t}$

where

v is the speed

d is the distance

t is the time taken

Here we know:

v = 24.0 m/s is the average speed

$d=1250 km = 1.25\cdot 10^6 m$ is the distance

Solving the equation, we find the time taken:

$t=\frac{d}{v}=\frac{1.25\cdot 10^6 m}{24.0 m/s}=52083 s$

And since

1 hour = 3600 s

The time in hours is

$t=52083 s \cdot \frac{1}{3600 s}=14.5 h$

6 0

4 years ago

The image represents a sound wave as it goes through several changes. Describe how the waves changes. where does it get louder?

Ksju [112]

Answer:

At point A. it gets kinda loud then at point B. it gets very loud than at point C. it gets quieter than at point D. it gets more silent.

Explanation:

Because you can tell when the waves get large it gets louder and then when the waves get more far apart then it get more quiet. Hope this helped!

4 0

3 years ago

Uncertainty in 21.0 C is A. 0.1 B. 0.2 C. 0.05