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bagirrra123 [75]
3 years ago
14

A satellite dish is in the shape of a parabolic surface. Signals coming from a satellite strike the surface of the dish and are

reflected to the​ focus, where the receiver is located. The satellite dish has a diameter of 10 feet and a depth of 2 feet. How far from the base of the dish should the receiver be​ placed?
Physics
1 answer:
LenKa [72]3 years ago
8 0

Answer: 3.125 ft

Explanation:

If this dish has the form of a concave upward parabola and its vertex p is at the origin, its corresponding equation is:

x^{2}=4py

Where:

x is the radius, which can be found by dividing the diameter d=10 ft by half. Hence x=\frac{d}{2}=\frac{10 ft}{2}=5 ft

y=2 ft is the depth

p is the vertex of the parabola, where its base is

Finding p:

p=\frac{x^{2}}{4y}

p=\frac{(5 ft)^{2}}{4(2 ft)}

Finally:

p=3.125 ft This is where the the receiver should be placed

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