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Vadim26 [7]
3 years ago
15

The force of gravity on the moon is approximately one sixth that of earth. the direct variation equation for weight on earth com

pared to wait on the moon is e=6m, where the e weight on the earth and m= weight on the moon what would be the weight of a 180 pound man on the moon
Mathematics
1 answer:
Inga [223]3 years ago
8 0
Plug in 180 for e and solve for m
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Find the solutions of the form x=a,y=0and x=0 ,y=b for the following equations: 2x+5y=10 and 2x+3y=6. is there any common soluti
Arlecino [84]

Answer:

 x=0 and y=2

Step-by-step explanation:

We have been given system of equations:

2x+5y=10     (1)

And 2x+3y=6     (2)

Subtract equation (2) from(1) we get:

2y=4

y=2

Now, substitute y=2 in equation(2) we get:

2x+3(2)=6

2x+6=6

2x=0

x=0

Hence, x=0 and y=2


8 0
3 years ago
Y=(2x-3)^5(2-x^4)^3 differentiate the function please
BARSIC [14]
\bf y=(2x-3)^5(2-x^4)^3\\\\
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\cfrac{dy}{dx}=\stackrel{\textit{product rule}}{[5(2x-3)^4\cdot 2(2-x^4)3]~~+~~[(2x-3)^5[3(2-x^4)^2(-4x^3)]]}
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\cfrac{dy}{dx}=10(2x-3)^4(2-x^4)^3~~-~~12x^3(2x-3)^5(2-x^4)^2
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\cfrac{dy}{dx}=\stackrel{\textit{common factor}}{2(2x-3)^4(2-x^4)^2}~[5(2-x^4)-6x^3(2x-3)]
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\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2~[10-5x^4-12x^4+18x^3]
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\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2(10-17x^4+18x^3)
5 0
3 years ago
PLS HELP I NEED ANSWER ASAP!<br> PPLS BE RIGHT!
Luba_88 [7]

Answer:

They used 6 vans and 3 buses

Step-by-step explanation:

x + y= 9

13x + 40y= 198

x= 9 - y

13(9 - y) + 40y= 198

117 - 13y + 40y= 198

27y= 81

y= 3

9-3= 6

4 0
3 years ago
Read 2 more answers
Compute $\sqrt{25^2-7^2}$.
EastWind [94]

Answer:

24

Step-by-step explanation:

\sqrt{25^2-7^2}\\\\=\sqrt{(25-7)(25+7)}\\\\=\sqrt{18(32)}\\\\=\sqrt{9*2*2^5}\\\\=\sqrt{3^2\cdot 2^6}\\\\=\sqrt{(3\cdot2^3)^2}\\\\=3\cdot2^3\\\\=3\cdot8\\\\=24

5 0
3 years ago
Consider the given geometric sequence.
Gala2k [10]
F5=(256)f1=16 hope this helps
7 0
3 years ago
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