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xenn [34]
3 years ago
10

There are 7 tigers at the zoo. Each year, the number of tigers increases by 10%. There are 15 eagles at the zoo. Each year, 2 ne

w eagles join the zoo.
Part A: Write functions to represent the number of tigers and eagles at the zoo throughout the years. (4 points)

Part B: How many tigers are at the zoo after 10 years? How many eagles are at the zoo after the same number of years? (2 points)

Part C: After approximately how many years is the number of tigers and eagles the same? Justify your answer mathematically. (4 points)
Mathematics
1 answer:
iren2701 [21]3 years ago
8 0
Part A: tigers- y= .10x + 7
eagles- y= 2x + 15

Part B: tigers - 17
eagles- 35

Part C: Not sure.
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If triangle abc, a=3, b=5 and c=7. Find the measure of angle b
krek1111 [17]

Answer:

β = arccos((a^2 + c^2 - b^2)/(2·a·c))

β = arccos((3^2 + 7^2 - 5^2)/(2·3·7)) = 38.21°

4 0
3 years ago
Read 2 more answers
Help this is due soon..
WARRIOR [948]

Answer:

y is skipping by 12 each time

Step-by-step explanation:

41+12=53

53+12= 65

65+12=77

hope this helps

7 0
3 years ago
Read 2 more answers
Plz can someone help me show work for these two problems!! <br><br> 3x + y = 13 <br><br> 2x - y = -1
Alisiya [41]

Answer:

3x +y = 13

Or, x=13-y/3......eqn(i)

Now putting the value of x

2x - y = - 1

Or, 2(13-y/3) - y = - 1

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3 0
3 years ago
John has four more nickels than dimes in his pocket, for a total of $1.25. Which equation could be used to determine the numbet
ahrayia [7]
So, you have to have your equation in terms of dimes. What you said about what he has: four more nickels than dimes in his pocket. Will help with our equation.
We know what a nickel and dime is worth. A nickel is .05 and a dime is .1
We don't know how many dimes are in his pocket, since we're trying to solve it.
.1x+(4+x).05=1.25; 
In the parenthesis, it shows how there are four more nickels. Let's solve it now.
.1x + (4+x).05=1.25
.1x + .2+ .05x = 1.25; Let's add like terms.
.15x + .2 = 1.25; Subtract .2 from both sides.
.15x= 1.05
1.05÷.15= 7 =x
There are 7 dimes in his pocket, let's check our answer.
We now know there are 11 nickels, since there are four more nickels than dimes.
11(.05) +.1(7) = 1.25
.55+ .7 = 1.25
Now that we've tried it, we know there are 7 dimes in his pocket.
Tell me if this helps!
7 0
3 years ago
Is 2.82842712475 a rational number
Galina-37 [17]
No---------------------------------
7 0
3 years ago
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