The first (and most typical) way to find distance of two points is by using the distance formula.

One alternative is the Manhattan metric, also called the taxicab metric. This option is much more complicated, and rarely used in high school math. d(x,y)=∑i|xi-yi|
Answer:
The probability that a randomly selected person gets incorrect result is 2.2 × 10⁻⁴
Step-by-step explanation:
The parameters given are;
The accuracy of the test for a person who has the respiratory synctial virus = 97%
The accuracy of the test for a person who does not have the respiratory synctial virus = 99%
We have;
a = TP =
b = FP
c = FN
d = TN
a/(a + c) = 0.97
d/(d + b) = 0.99
a/(a + b) = 0.97*0.0055/(0.97*0.0055 + (1 - 0.99)*(1-0.0055))
PPV = 0.349 = 34.9%
Therefore, we have;
a/(a + c) = 0.97 and
a/(a + b) = 0.349
0.97(a + c) =0.349(a + b)
(0.97 - 0.349)a = 0.349·b - 0.97·c
a = (0.349·b - 0.97·c)0.621
b × (1 - 0.0055) = (1 - 0.97)×(1 - 0.0055)
b = 1 - 0.97 = 0.03
Similarly,
c = 1 - 0.99 = 0.01
The proportion of the population that have false positive and false negative = 0.03 + 0.01 = 0.04 = 4%
The probability that a randomly selected person gets incorrect result = 0.04×0.0055 = 0.00022.
Answer:
{-4,-1,1,4,7,8,15,18}
Step-by-step explanation:
The range of this function is a universal set that contains all elements of each set
And is;
{-4,-1,1,4,7,8,15,18}
1.30 represents the rate of growth of the mold spores. This decimal is a representation of the percentage growth, which would be 130%.
Since the function is written in terms of weeks, x will equal 4 to represent the amount of spores after 4 weeks. Plug the value into the function:

Rounded to the nearest ones value, there will be 985 mold spores after 4 weeks.
<u>Complete question:</u>
Refer the attached diagram
<u>Answer:</u>
In reference to the attached figure, (-∞, 2) is the value where (f-g) (x) negative.
<u>Step-by-step explanation:</u>
From the attached figure, it shows that given data:
f (x) = x – 3
g (x) = - 0.5 x
To Find: At what interval the value of (f-g) (x) negative
So, first we need to calculate the (f-g) (x)
(f – g ) (x) = f (x) – g (x) = x-3 - (- 0.5 x)
⇒ (f - g) (x) =1.5 x - 3
Now we are supposed to find the interval for which (f-g) (x) is negative.
⇒ (f - g) (x) = x - 3+ 0.5 x = 1.5 x – 3 < 0
⇒ 1.5 x – 3 < 0
⇒ 1.5 x < 3
⇒ 
⇒ x < 2
Thus for (f - g) (x) negative x must be less than 2. Thereby, the interval is (-∞, 2). Function is negative when graph line lies below the x - axis.