The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
Hello Austint1414
The answer in standard form would be <u><em>70,633,999,564,087,001</em></u>
:)
Divide 3 from both sides to get a=57/3 then a=19
Paralalell means that is has the same slope
y=mx+b
m=slope
y=-1x-2
slope=-1
the equation of a line that passes through the point (x1,y1) and has a slope of m is y-y1=m(x-x1)
given
(2,-2) and slope is -1
y-(-2)=-1(x-2)
y+2=-x+2
minus 2
y=-x
answer is y=-x
Answer:
21
Step-by-step explanation:
Similar triangles. MNL is just ABC but 3/4 the size.
x = 8*3/4 = 6
perimeter woudl be 6+6+9 = 21
