The problem involves the conversion of potential energy to kinetic energy as the object falls from rest. Energy is conserved, so the equation used is:
PEi + KEi = PEf + KEf
Since the object is falling from rest, the initial kinetic energy is zero. Also, since the object hits the ground at its final position, the final potential energy is zero. This leaves:
PEi = KEf
mgh = 1/2 mv^2
*cancel out mass on both sides of the equation
gh = 0.5v^2
v = sqrt(2gh) = sqrt(2*9.81*4.5) = 9.40 m/s --> final ans.
Answer:
The maximum height obtained by the object is approximately 31.855 m
Explanation:
The vertical velocity of the object = 25.0 m/s
The height reached by the object, is given by the following formula;
v² = u² - 2 × g × h
Where;
u = The initial velocity of the object = 25.0 m/s
v = The final speed of the object = 0 m/s at maximum height
h = The maximum height obtained by the object
g = The acceleration due to gravity = 9.81 m/s²
Substituting the values, gives;
0² = (25.0 m/s)² - 2 × 9.81 m/s² × h
2 × 9.81 m/s² × h = (25.0 m/s)²
h = (25.0 m/s)²/(2 × 9.81 m/s²) ≈ 31.855 m
The maximum height obtained by the object, h ≈ 31.855 m.
Answer:
1.696 × 10^(-7) m on the y axis.
Explanation:
We are given the electric field as;
E = < 0, 5 × 10⁴, 0> N/C
This is written in (x, y, z) co-ordinates. So it means that it lies on the y-axis.
So,
E = 5 × 10⁴ N/C in the y direction.
Formula for Electric field is;
E = kq/r²
where;
k is a constant with a value of 8.99 x 10^(9) N.m²/C²
q is charge on the proton = 1.6 × 10^(-19) C
r is the distance
Thus, making r the subject gives;
r = √(kq/E)
Plugging in the relevant values gives;
r = √(8.99 × 10^(9) × 1.6 × 10^(-19)/(5 × 10⁴))
r = 1.696 × 10^(-7) m on the y axis.
Answer:
89.16pounds
Explanation:
The equation that defines this problem is as follows
W=k/X^2
where
W=Weight
K=
proportionality constant
X=distance from the center of Earth
first we must find the constant of proportionality, with the first part of the problem
k=WX^2=131x3960^2=2054289600pounds x miles^2
then we use the equation to calculate the woman's weight with the new distance
W=2054289600/(4800)^2=89.16pounds
