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mario62 [17]
3 years ago
13

From hottest to coolest, the order of the spectral types of stars is _________. From hottest to coolest, the order of the spectr

al types of stars is _________. OBAFGKM OMKGFBA OBAGFKM ABFGKMO ABCDEFG
Physics
1 answer:
Dimas [21]3 years ago
6 0

Answer:

OBAFGKM

Explanation:

Most stars are classified using the Morgan-Keenan system, which consists of assigning a letter to the star depending on its temperature. The hottest stars are type O, and the coldest stars are type M. As for their color, the coldest stars tend to have red color and the hottest have blue colors.

Within each of these divisions (OBAFGKM), there is another division that are the numbers from 0 to 9: 0 is hotter and 9 colder, to get a better classification of a star.

The order of the letters of the Morgan – Keenan system classification, according to the temperatures is as follows:

O: temperatures greater than 33,000K

B: temperatures between 10,000K and 33,000K

A: temperatures between 7,500K and 10,000K

F: temperatures between 6000K and 7.500K

G: temperatures between 5,200K and 6,000K

K: temperatures between 3,700k and 5,200K

M: temperatures below 3,700 K

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Solenoid 2 has twice the radius and six times the number of turns per unit length as solenoid 1. The ratio of the magnetic field
Xelga [282]

Answer:

6

Explanation:

The magnetic field inside a solenoid is given by the following formula:

B = \mu_{0}nI

where,

B = Magnetic Field Inside Solenoid

μ₀ = permittivity of free space

n = No. of turns per unit length

I = Current Passing through Solenoid

For Solenoid 1:

B_{1} = \mu_{0}n_{1}I  ------------------- equation 1

For Solenoid 2:

n₂ = 6n₁

Therefore,

B_{1} = \mu_{0}n_{2}I\\B_{1} = 6\mu_{0}n_{1}I  ----------------- equation 2

Diving equation 1 and equation 2:

\frac{B_{2}}{B_{1}} = \frac{6\mu_{0}nI}{\mu_{0}nI}\\\\\frac{B_{2}}{B_{1}} = 6

Hence, the correct option is:

<u>6</u>

8 0
2 years ago
The weight of an astronaut plus his space suit on the Moon is only 250 N. (a) How much does the suited astronaut weigh on Earth?
Evgesh-ka [11]

Answer:

a)1500N

b)153.06kg

Explanation:

F = ma

g(moon) = is the acceleration due to gravity on the moon

g(earth) is the acceleration due to gravity on the earth

g(moon) = 1/6g(earth)

g(earth) =6g(moon)

F(gearth) = mg(earth)

               = m 6g(moon)

               = 6 × 250

               = 1500N

b) F(gearth) = mg(earth)

m = F /g

 = 1500/9.8

 = 153.06kg

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