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2 years ago

12

build three straight ramps on the stage one ramp should be nearly flat and another should be extremely steep the last ramp shoul

d have a steepness somewhere in between

1 answer:

notsponge [240]2 years ago

3 0

Answer:

hope this helps

Explanation:

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The equation for momentum is p = mv, where p is momentum, m is mass, and v

Tasya [4]

Answer:

p = mv, where p is momentum, m is mass, and v is velocity.

a. ) m = 12kg v = 14m/s

Momentum (p) = mv

= 12kg × 14m/s

= 168kg•m/s

b.) momentum (p) = 35 kg•m/s

velocity = 3m/s

p = mv

make m the subject

divide both sides by v

we get

m = p/v

Therefore m is

m = 35 kg•m/s / 3m/s

m = 11.67kg

Therefore the mass of the object is 11.67kg

Hope this helps

3 0

3 years ago

A particle with a mass of 2.3 × 10-20 kg is oscillating with simple harmonic motion with a period of 3.0 × 10-5 s and a maximum

baherus [9]

Answer:

angular frequency is 209439.51 rad/sec

maximum displacement is 0.010504 m

Explanation:

Given data

mass = 2.3 × 10^-20 kg

period = 3.0 × 10^-5 s

maximum speed = 2.2 × 10^3 m/s

to find out

the angular frequency and maximum displacement

solution

we know angular frequency formula that is

angular frequency = 2 π / period

put here period value we get angular frequency

angular frequency = 2 π / 3.0 × 10^-5

angular frequency is 209439.51 rad/sec

maximum displacement formula is

speed = angular frequency × maximum displacement

put all value and we get maximum displacement

maximum displacement = 2.2 × 10^3 / 209439.51

maximum displacement is 0.010504 m

8 0

3 years ago

Find the distance between two slits that produces the first minimum for 410-nm violet light at an angle of 45.0°

Tpy6a [65]

Answer:

Distance between slits, $d=2.89\times 10^{-7}\ m$

Explanation:

It is given that,

Wavelength, $\lambda=410\ nm=410\times 10^{-9}\ m$

Angle, $\theta=45$

We need to find the distance between two slits that produces first minimum. The equation for the destructive interference is given by :

$d\ sin\theta=(n+\dfrac{1}{2})\lambda$

For first minimum, n = 0

So, $d\ sin\theta=(\dfrac{1}{2})\lambda$

d is the distance between slits

So, $d=\dfrac{1/2\lambda}{sin\theta}$

$d=\dfrac{1/2\times 410\times 10^{-9}}{sin(45)}$

$d=2.89\times 10^{-7}\ m$

So, the distance between two slits is $2.89\times 10^{-7}\ m$ . Hence, this is the required solution.

6 0

3 years ago

Based on Archimedes' principle, we know that if an object displaces a given weight of water, then the object is being buoyed up

Virty [35]

True. If the amount displaced is more than the mass, it floats. If the amount is less than the mass, it will sink.

8 0

3 years ago

Read 2 more answers

An electron moving in a direction perpendicular to a uniform magnetic field at a speed of 1.6 107 m/s undergoes an acceleration

umka2103 [35]

Answer:

B = 0.024T positive z-direction

Explanation:

In this case you consider that the direction of the motion of the electron, and the direction of the magnetic field are perpendicular.

The magnitude of the magnetic force exerted on the electron is given by the following formula:

$F=qvB$ (1)

q: charge of the electron = 1.6*10^-19 C

v: speed of the electron = 1.6*10^7 m/s

B: magnitude of the magnetic field = ?

By the Newton second law you also have that the magnetic force is equal to:

$F=qvB=ma$ (2)

m: mass of the electron = 9.1*10^-31 kg

a: acceleration of the electron = 7.0*10^16 m/s^2

You solve for B from the equation (2):

$B=\frac{ma}{qv}\\\\B=\frac{(9.1*10^{-31}kg)(7.0*10^{16}m/s^2)}{(1.6*10^{-19}C)(1.6*10^7m/s)}\\\\B=0.024T$

The direction of the magnetic field is found by using the right hand rule.

The electron moves upward (+^j). To obtain a magnetic forces points to the positive x-direction (+^i), the direction of the magnetic field has to be to the positive z-direction (^k). In fact, you have:

-^j X ^i = ^k

Where the minus sign of the ^j is because of the negative charge of the electron.

Then, the magnitude of the magnetic field is 0.024T and its direction is in the positive z-direction

8 0

3 years ago