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strojnjashka [21]
3 years ago
11

A stress of 210 MPa is applied to a low-carbon steel with an elastic modulus of 211 GPa. After the stress is applied and then re

moved, we note that the permanent strain at 0 stress is 0.1. What was the total strain when the stress was equal to 210 MPa

Physics
1 answer:
Katen [24]3 years ago
3 0

Answer:

Total strain when the stress was equal to 210 MPa = 0.101

Explanation:

See attached pictures.

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When the shadow of the moon appears on earths surface what is occuring?
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Un auto recorre 212 km en un tiempo de 3.1 h.Calcular su rapidez en m/s
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Para hacerlo a m/s un método muy práctico es sólo dividir entre 3.6, por cuestiones de conversiones, lo puedes comprobar.

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Comprobación :

V= d / t

V= 212 m / 18000 seg <---- nota que aquí los segundos son de las 3.1hrs  

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3 years ago
Which simple machine is NOT correctly matched with an appropriate task for its use?
Tcecarenko [31]
The simple machine that is not correctly matched with  its appropriate task is the inclined plane because there is no such big ramp that is as high as 1 storey building, the appropriate task would be Lifting a heavy box and moving it across a room. and for the pulley : <span>Moving a heavy box up to the second floor of a building.</span>
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3 years ago
astone is thrown upwards with an initial velocity of 25m/s atan angle of 30 to the ground.what is the work out the stones horiza
vovikov84 [41]

Answer:

<u>Range</u><u> </u><u>is</u><u> </u><u>6</u><u>2</u><u>.</u><u>5</u><u> </u><u>metres</u>

Explanation:

Time of flight

t =  \frac{2u \sin( \theta) }{g}

for range, acceleration is zero

from second newton's equation:

S = ut +  \frac{1}{2}  {at}^{2}

but a = 0:

let range be x:

x = ut \\ x =  \frac{2 {u}^{2}  \sin( \theta) }{g}  \\  \\ x =  \frac{ \{2 \times 25 {}^{2}  \sin(30 \degree)  \}}{10}  \\  \\ x = 62.5 \: metres

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4 0
3 years ago
A loop of wire is in a magnetic field such that its axis is parallel with the field direction. Which of the following would resu
iren2701 [21]

Answer:

All the 4 options

Explanation:

Electromagnetic induction occurs when the magnetic flux through a coil of wire is changing over time:

\epsilon = -\frac{\Delta \Phi}{\Delta t}

where

\epsilon is the emf induced in the coil

\Delta \Phi is the variation of magnetic flux

\Delta t is the variation of time

The presence of an emf in the coil will generated an induced current.

The magnetic flux through the coil is given by

\Phi = BA cos \theta

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B is the intensity of the magnetic field

A is the area of the coil

\theta is the angle between the direction of the field and the axis of the coil

We see that any actions that changes one of these 3 variables will change the magnetic flux through the coil, so it will also induce a current.

The 4 options are:

1.Moving the loop outside of the magnetic field region. --> this will decrease the intensity of the magnetic field, B, therefore it will change the flux, and it will induce a current

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3.Change the magnitude of the magnetic field. --> this will change the magnitude of B, so this will also change the flux, and therefore will induce a current

4.Change the diameter of the loop --> this will change the area of the coil A, so this will also change the flux, and therefore will induce a current

Therefore, all 4 options are correct.

6 0
3 years ago
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