Answer:
a) T = 2.997 s
b) K = 14.3 J
c) φ = 0.444 rad
Explanation:
a) Determine its period
The pendulum simple’s period is:
T = 2π
Where l: Pendulum’s length
g = 9.8 m/s2
T = 2π
T = 2.997 s
b) Total energy
Initially his total energy is kinetic
K = 
K = 
K = 14.3 J
c) Maximum angular displacement
φ = 
φ = 
φ = 0.444 rad
Answer:
D=387.28m
Explanation:
At the moment where the toss is made 
, so we need both equations:
For the red car:
With initial speed of 0 and acceleration of 6.12m/s^2.
For the green car:
With 
and Xo = 200m
Since both positions will be the same:
Solving for t:
t1 = -5.8s and t1 =11.25s
Replacing t = 11.25 on either equation to find the displacement:
Answer:
The minimum possible coefficient of static friction between the tires and the ground is 0.64.
Explanation:
if the μ is the coefficient of static friction and R is radius of the curve and v is the speed of the car then, one thing we know is that along the curve, the frictional force, f will be equal to the centripedal force, Fc and this relation is :
Fc = f
m×(v^2)/(R) = μ×m×g
(v^2)/(R) = g×μ
μ = (v^2)/(R×g)
= ((25)^2)/((100)×(9.8))
= 0.64
Therefore, the minimum possible coefficient of static friction between the tires and the ground is 0.64.
Answer:
Weight
Explanation:
The second law of motion by Newton can be used to determine weight.
