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umka21 [38]
3 years ago
12

An electron moves in a circular path perpendicular to a uniform magnetic field with a magnitude of 1.98 mT. If the speed of the

electron is 1.53 107 m/s, determine the following.(a) the radius of the circular path
Physics
1 answer:
Mariulka [41]3 years ago
8 0

Answer:

4.4 cm

Explanation:

B = 1.98 mT = 1.98 x 10^-3 T, v = 1.53 x 10^7 m/s, m = 9.1 x 10^-31 kg

q = 1.6 x 10^-19 C

(a) The force due to the magnetic field is balanced by the centrpetal force

mv^2 / r = q v B

r = m v / q B

r = (9,1 x 10^-31 x 1.53 x 10^7) / (1.98 x 10^-3 x 1.6 x 10^-19)

r = 0.044 m = 4.4 cm

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Zolol [24]

Answer:

0.4 m/s2

Explanation:

mass: 25kg

net force: 10 N

acceleration: ?

net force ÷ by mass= acceleration

10 N ÷ 25 Kg = 0.4 m/s2

6 0
3 years ago
The 10 Ω resistor in the figure is dissipating 40 W of power. (Figure 1) How much power is the 20Ω resistor dissipating?
Scilla [17]
I = E / R = 1 amperes through the 20 ohm resistor.

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3 years ago
Read 2 more answers
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weqwewe [10]

Answer

Correct Answer is B,D, F and G

Explanation:

If a kid has any type of delays in his physical or mental growth then he need intervention service.

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8 0
3 years ago
Cool facts about satellites ???
svetoff [14.1K]
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7 0
3 years ago
A Michelson interferometer uses light with a wavelength of 452.446 nm. Mirror M2 is slowly moved a distance x, causing exactly 2
I am Lyosha [343]

Answer:

Option b. Dark spot

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