The frictional force is 15 N
Explanation:
In order to solve this problem, we can apply Newton's second law of motion, which states that the net force acting on an object is equal to the product between its mass and its acceleration:
where
is the net force
m is the mass
a is the acceleration
Here we are just interested in the situation along the horizontal direction. The net force acting on the block is:
where
is the applied force (forward)
is the frictional force (backward)
m = 5 kg is the mass of the block
is the acceleration
Substituting into the equation and solving, we find the frictional force:
Learn more about Newton's second law:
brainly.com/question/3820012
#LearnwithBrainly
Answer:
D. Both are used by radio stations to transmit sound
Explanation:
acceleration of rocket is given here as
now we know that
now integrating both sides
here since its given that rocket will accelerate for t = 10 s
so here we have
so after t = 10 s the speed of rocket will be 130 m/s upwards
Answer:
The torque required is 0.024Nm
Explanation:
Solution:
Data Given;
Mass of sphere = 80kg
Radius of sphere = 0.1m
Time = 5s
Angle = 1.5radians
To calculate the torque is required to twist and hold the sphere, we use the formula;
Torque = Inertia * angular acceleration -----------------------------1
where,
Inertia = 1/2 mr²---------------------------------------------------------------2
Substituting into the formula, we have
= 1/2 * 80*0.1²
= 1/2 * 0.8
= 0.4kgm²
Angular acceleration = angular velocity/time----------------------3
Where angular velocity = ∅/time
Substitution into equation 3, we have
= 1.5/5²
= 1.5/25
= 0.06rad/s²
Coming back to equation 1,
Substituting the values obtained into equation 1, we have
Torque = Inertia * angular acceleration
= 0.4 * 0.06
= 0.024Nm