A) 4a+3w
b) 2b+h
c) 3(w+h)
d) (4a+3w)(2b+h) - 3(w+h)
just expand brackets for d and simplify
The smallest 3 common multiples of 2 and 3 are 6, 12, and 18 .
The smallest 3 common multiples of 3 and 6 are also 6, 12, and 18 .
First solve the length of side BC, CD, EF and FA
Since BC = CD = sqrt( 10^2 + 10^2)
BC = CD = 14.1421
FA = EF = sqrt(10^2 + 20^2)
= 23.3607
So the perimeter = 10 + 10 + 14.1421 + 14.1421 + 23.3607
= 93
The area is made up be triangle FAE, rectangle ABDE and
triangle BCD
A = 0.5(20)(20) + (10)(20) + 0.5(20)(10)
<span>A = 500 sq units</span>
The two numbers I think is 3&6 because this is a trick question
