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antoniya [11.8K]
3 years ago
7

A box 3 centimeter high, 4 centimeters wide, and 6 centimeters long can hold 50 grams of clay. A second box has twice the height

, 3 times the width and the same length as the first box. How many grams of clay can it hold? Show your work.
Mathematics
1 answer:
kolbaska11 [484]3 years ago
4 0
-------------------------------------------------------------------------------
First Box:
 -------------------------------------------------------------------------------
Volume of teh box = 3 x 4 x 6 = 72 cm³

-------------------------------------------------------------------------------
Clay per cm³
-------------------------------------------------------------------------------
72cm³ = 50g of clay.
1 cm³ = 25/36g of clay.

-------------------------------------------------------------------------------
Second box :
-------------------------------------------------------------------------------
Length = 6cm
Width = 3 x 4 = 12cm
Height = 3 x 2 = 6m

Volume = 6 x 12 x 6 = 432 cm³

-------------------------------------------------------------------------------
Find Volume of clay :
-------------------------------------------------------------------------------
1 cm³ = 25/36 g
432 cm³ = 25/36 x 432 = 300g

-------------------------------------------------------------------------------
Answer: 300g of clay
-------------------------------------------------------------------------------
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If xy + y² = 6, then the value of dy/dx at x= -1 is<br>​
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Hi there!

\large\boxed{\text{At (-1, -2), }\frac{dy}{dx} = -\frac{2}{5}}}

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<em></em>

<u>Step-by-step explanation:</u>

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If these assumptions hold, then the distance d in Km can be calculated by using the haversine formula:

\large d=2R*arcsin\left(\sqrt{sin^2((\varphi_2-\varphi_1)/2)+cos(\varphi_1)cos(\varphi_2)sin^2((\lambda_2-\lambda_1)/2)}\right)

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\large (\varphi_1, \lambda_1) are the latitude and longitude of the starting point in radians.

\large (\varphi_2, \lambda_2) are the latitude and longitude of the end point in radians.

R = radius of  Earth in kilometers.

Be careful to convert the angles into radians before computing the trigonometric functions. This can be done by cross-multiplication knowing that 180° ≅ 3.141592654 radians.

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\large \varphi_1 = 48° = 0.837758041 radians

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b)

Assuming that the shoes where left and found the same year, there are 22 days from April 30th  to May 22nd , so they traveled for around 22 days <em>(this may vary slightly depending on the exact time the shoes were left and found) </em>

c)

They traveled 2,052.583 Km in 22 days.

22 days equals 22*24 = 528 hours.

By <em>cross-multiplication </em>

528 h _______  2,052.583 Km

1 h __________ x Km

x =  2,052.583/528 ≅ 3.887 Km

So they traveled at a rate of 3.887 Km/h

8 0
3 years ago
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