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omeli [17]
2 years ago
9

Which expression is equivalent to Negative 28 x y 35 y? 7 y (Negative 4 x y 5 y) 7 x (negative 4 x 5 y) 7 x (negative 4 y 5 y) 7

y (Negative 4 x 5).
Mathematics
1 answer:
GREYUIT [131]2 years ago
3 0

You can use the distributive property of multiplication over addition to find the equivalent expression to the given expression.

The expression which is equivalent to the given expression is given by

Option D: 7y(-4x + 5)

<h3>What are equivalent expressions?</h3>

Those expressions who might look different but their simplified forms are same expressions are called equivalent expressions.

<h3>What is distributive property of multiplication over addition?</h3>

Suppose a, b and c are three numbers. Then we have:

a(b + c) = a \times b + a \times c

(a(b+c) means a multiplied to (b+c). The sign of multiplication is usually hidden when using symbols and both quantities which are in multiplication are written together without space)

<h3>Using the above property and the fact that 28 and 35 are multiples of 7 to get the equivalent expression</h3>

The given expression is -28xy + 35y

Since 28 = 7 times 4 and 35 = 7 times 5

Thus,

-28xy + 35y = -7 \times 4 \times x \times y + 7 \times 5 \times y = 7y(-4x + 5)

Thus,

The expression which is equivalent to the given expression is given by

Option D: 7y(-4x + 5)

Learn more about equivalent expressions here:
brainly.com/question/10628562

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The average weight of the class of 35 students was 45 KG. with the admission of a new student the average weight came down to 44
melamori03 [73]

The weight of the new student is 27 kg.

Average weight

= total weight ÷total number of students

<h3>1) Define variables</h3>

Let the total weight of the 35 students be y kg and the weight of the new student be x kg.

<h3>2) Find the total weight of the 35 students</h3>

<u>45 =  \frac{y}{35}</u>

y= 35(45)

y= 1575 kg

<h3>3) Write an expression for average weight of students after the addition of the new student</h3>

New total number of students

= 35 +1

= 36

Total weight

= total weight of 35 students +weight of new students

= y +x

44.5  =  \frac{y + x}{36}

<h3>4) Substitute the value of y</h3>

44.5 =  \frac{1575 + x}{36}

<h3>5) Solve for x</h3>

36(44.5)= 1575 +x

1602= x +1575

<em>Subtract 1575 from both sides:</em>

x= 1602 -1575

x= 27

Thus, the weight of the new student is 27 kg.

7 0
2 years ago
What is the approximate perimeter?
vladimir1956 [14]
300^2 + 500^2 = c^2
9000 + 250000=c^2
340000=c^2
sqrt (340000) = c
c = 583
300 + 500 + 583 = 1383
1380 is the perimeter
8 0
2 years ago
Please help and EXPLAIN
creativ13 [48]
Okay, all of these pairs add up to 1 or 100%, except for one pair. I'll convert them all to decimals, so all must add up to 1.

3/8 = 0.375
0.625 + 0.375 = 1

62% = 0.62
0.38 + 0.62 = 1

7/8 = 0.875
0.875 + 0.125 = 1

70% = 0.70
1/3 <span>≈</span> 0.33
0.70 + 0.33 = 1.03

So the last pair of probabilities(70%, 1/3) does not belong with the other three because it does not add up to 1 like the others.
8 0
3 years ago
. A special safe lets you choose from 9 symbols for a 3-symbol-long pass code. You may enter a symbol any number of times. How m
Lady_Fox [76]

The question is an illustration of combination and there are 729 potential pass codes available

<h3>How to determine the number of potential pass codes?</h3>

The given parameters are

Symbols available = 9

Length of pass code = 3

From the question, we understand that a symbol may be entered any number of times.

This means that each of the 9 available symbols can be used three times

So, the number of potential pass codes is

Passcodes = 9 * 9 * 9

Evaluate the product

Passcodes = 729

Hence, there are 729 potential pass codes available

Read more about combination at:

brainly.com/question/11732255

#SPJ1

4 0
2 years ago
SOMEONE PLEASE HELP ME WITH THIS!!!!
denis23 [38]

Answer:

D.

Step-by-step explanation:

115x + 170 = 630

Subtract 170 from each side of the equals,

115x = 460

Divide 460 by 115,

4

Thus, D is your correct answer.

<em>Answered by:</em>

matthewarvin06

Hey! Thanks for reading my answer. If this helped you in any way, please rate or say thanks! It's really appreciated. If you have any further questions, please let me know. Thanks!

7 0
2 years ago
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