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omeli [17]
3 years ago
9

Which expression is equivalent to Negative 28 x y 35 y? 7 y (Negative 4 x y 5 y) 7 x (negative 4 x 5 y) 7 x (negative 4 y 5 y) 7

y (Negative 4 x 5).
Mathematics
1 answer:
GREYUIT [131]3 years ago
3 0

You can use the distributive property of multiplication over addition to find the equivalent expression to the given expression.

The expression which is equivalent to the given expression is given by

Option D: 7y(-4x + 5)

<h3>What are equivalent expressions?</h3>

Those expressions who might look different but their simplified forms are same expressions are called equivalent expressions.

<h3>What is distributive property of multiplication over addition?</h3>

Suppose a, b and c are three numbers. Then we have:

a(b + c) = a \times b + a \times c

(a(b+c) means a multiplied to (b+c). The sign of multiplication is usually hidden when using symbols and both quantities which are in multiplication are written together without space)

<h3>Using the above property and the fact that 28 and 35 are multiples of 7 to get the equivalent expression</h3>

The given expression is -28xy + 35y

Since 28 = 7 times 4 and 35 = 7 times 5

Thus,

-28xy + 35y = -7 \times 4 \times x \times y + 7 \times 5 \times y = 7y(-4x + 5)

Thus,

The expression which is equivalent to the given expression is given by

Option D: 7y(-4x + 5)

Learn more about equivalent expressions here:
brainly.com/question/10628562

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6 0
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The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 33,208 miles, with a standard
avanturin [10]

Answer:

There is a 92.32% probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 33,208 miles, with a standard deviation of 2503 miles.

This means that \mu = 33208, \sigma = 2503.

What is the probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct?

This is the pvalue of Z when X = 33208+633 = 33841 subtracted by the pvalue of Z when X = 33208 - 633 = 32575

By the Central Limit Theorem, we have t find the standard deviation of the sample, that is:

s = \frac{\sigma}{\sqrt{n}} = \frac{2503}{\sqrt{49}} = 357.57

So

X = 33841

Z = \frac{X - \mu}{\sigma}

Z = \frac{33841 - 33208}{357.57}

Z = 1.77

Z = 1.77 has a pvalue of 0.9616

X = 32575

Z = \frac{X - \mu}{\sigma}

Z = \frac{32575- 33208}{357.57}

Z = -1.77

Z = -1.77 has a pvalue of 0.0384.

This means that there is a 0.9616 - 0.0384 = 0.9232 = 92.32% probability that the sample mean would differ from the population mean by less than 633 miles in a sample of 49 tires if the manager is correct.

4 0
3 years ago
How to work it out<br> And who drove farther and how many miles farther
OlgaM077 [116]
Easy, just divide
kelly=440mi/8hr=220mi/4hr=110mi/2hr=55mi/1hr
alberto=468mi/9hr=156mi/3hr=52mi/1hr

55>52

kelly drove 55mi in 1 hour
55-52=3
she drove 3 miles more  in 1 hour
5 0
3 years ago
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