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barxatty [35]
3 years ago
6

5. Sue is 20 years old and Anne is 10 years old. How many years ago was Sue 3 times as old as Anne?

Mathematics
2 answers:
ololo11 [35]3 years ago
8 0
5 years ago :) hope I helped
lesya [120]3 years ago
6 0
Sue is going to be 23
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What is the answer I need to know
kolezko [41]
K = -18 to check, -4 + k/3 = -10 is the equation. -18/3 = -6, and -4 + -6 = -10. Mark as branliest if you can. :)
3 0
3 years ago
To practice for a competition, Sonya swam 0.94 kilometer in the pool each day for 3 weeks. How many meters did Sonya swim in tho
Strike441 [17]

Answer:

Distance swam by Sonya in 3 weeks = 19740 m

Step-by-step explanation:

To practice for a competition, Sonya swam 0.94 kilometer in the pool each day for 3 weeks.

Number of days in 1 week = 7

Number of weeks she swam = 3

Total number of days she swam = 3 x 7 = 21 days

Distance swam per day = 0.94 km

Total distance swam = Total number of days she swam x Distance swam per day

Total distance swam = 21 x 0.94 = 19.74 km = 19.74 x 1000 m = 19740 m

Distance swam by Sonya in 3 weeks = 19740 m

7 0
3 years ago
^*^*^*^*^*^*^*^*^*^*^*^*^*^*^*
Viefleur [7K]
I hope this helps you

4 0
2 years ago
Find the length of side a<br><br> a A. 12 <br>B. 144 <br>C. 1 194 <br>D. 8​
lukranit [14]

Answer:

12

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Tan^2 70° -sec^2 70°​
kipiarov [429]

Answer:

-1

Step-by-step explanation:

We need to find the value of tan² 70° -sec² 70°​.

We know that,

\sec^2\theta-\tan^2\theta=1 ...(1)

We can write the given expression as :

tan² 70° -sec² 70° = -(-tan² 70° +sec² 70°)

=-(sec² 70°-tan² 70°)

Using identity (1)

=-(1)

= -1

Hence, the value of the given expression is -1.

4 0
2 years ago
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