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MAXImum [283]
3 years ago
13

Subtract express your answer in simplest form 5/8-3/8=?

Mathematics
2 answers:
olchik [2.2K]3 years ago
6 0
The answer is 2/8. Hope this helps.
netineya [11]3 years ago
3 0
Since the two fractions already have a common denominator, we can subtract them with no issues:

\frac{5}{8} - \frac{3}{8} =  \frac{2}{8}

Since 2 and 8 have 2 as a common factor, we can use that to reduce it down to

\frac{2}{8}\div \frac{2}{2} = \frac{1}{4}
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3(y+2)=30 one solution​
SVEN [57.7K]
The answer to this problem is 6
6 0
2 years ago
Order the 9 ( yes 9 including Pluto )planets from smallest to biggest according to volume
hammer [34]

Answer:

Pluto has a density of 1.86 grams per cubic centimeter

Mercury has a mass of 3375.9  kilograms

Mars has a volume of 1.6318 x 10¹¹ km³

The volume of Venus is 9.38 x 1011 km3

The Earth has a volume of about 1,083,206,916,846 cubic kilometers

volume of 15 trillion cubic miles which is 62 trillion cubic kilometers

The planet has a volume of 6.83x1013 cubic kilometers

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hope this helps and feel free to give brainiest

4 0
3 years ago
Which represents the solution set of the inequality 2.9(x+8)<26.1
alukav5142 [94]
The answer is x is less than 1.

4 0
3 years ago
Read 2 more answers
Given the expression -7+6i/2+3i , perform the indicated operation and write the answer in the form a + bi.
Andre45 [30]
\dfrac{-7+6i}{2+3i}\times\dfrac{2-3i}{2-3i}=\dfrac{(-7+6i)(2-3i)}{(2+3i)(2-3i)}=\dfrac{4+29i}{4-9i^2}=\dfrac4{13}+\dfrac{29}{13}i
8 0
2 years ago
Given sin theta= 6/11 and sec theta < 0, find cos theta and tan theta.
bekas [8.4K]

Answer: option a.

Step-by-step explanation:

By definition, we know that:

cos^2(\theta)=1-sen^2(\theta)\\\\tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

Substitute sin(\theta)=\frac{6}{11} into the first equation, solve for the cosine and simplify. Then, you obtain:

cos(\theta)=\±\sqrt{1-(\frac{6}{11})^2}\\\\cos(\theta)=\±\sqrt{\frac{85}{121}}\\\\ cos(\theta)=\±\frac{\sqrt{85}}{11}

As sec\theta then cos\theta:

cos(\theta)=-\frac{\sqrt{85}}{11}

Now we can find tan\theta:

tan\theta=\frac{\frac{6}{11}}{-\frac{\sqrt{85}}{11}}\\\\tan\theta=-\frac{6\sqrt{85}}{85}

4 0
3 years ago
Read 2 more answers
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