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3 years ago

Subtract express your answer in simplest form 5/8-3/8=?

Mathematics

2 answers:

olchik [2.2K]3 years ago

6 0

The answer is 2/8. Hope this helps.

netineya [11]3 years ago

3 0

Since the two fractions already have a common denominator, we can subtract them with no issues:

$\frac{5}{8} - \frac{3}{8} = \frac{2}{8}$

Since 2 and 8 have 2 as a common factor, we can use that to reduce it down to

$\frac{2}{8}\div \frac{2}{2} = \frac{1}{4}$

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Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave

Colt1911 [192]

Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\sigma}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

$P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\ \\ =1-P(z\ \textless \ -0.5410) \\ \\ =1-0.29426=\bold{0.7057}$

Part B:

</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)$

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3 years ago

I need help like really bad

serg [7]

Answer:

Step-by-step explanation:

14/15 is less than 7/5

6 0

3 years ago

Read 2 more answers

Please please help me

Alex73 [517]

Answer:

x = 5.5

Step-by-step explanation:

Given 2 secants intersecting the circle from a point outside the circle then

The product of the external part and the entire part of one secant is equal to the product of the external part and the entire part of the other secant, that is

x(x + 14) = 6(6 + 12)

x² + 14x = 6 × 18 = 108 ( subtract 108 from both sides )

x² + 14x - 108 = 0 ← in standard form

with a = 1, b = 14 and c = - 108

Using the quadratic formula to solve for x

x = ( - b ± $\sqrt{b^2-4ac}$ ) / 2a