Solve the equation: x2 - 12x = -36

2 answers:

6 0

$x^2-12x=-36\ \ \ |add\ 36\ to\ both\ sides\\\\x^2-12x+36=0\\\\x^2-2x\cdot6+6^2=0\ \ |use\ (a-b)^2=a^2-2ab+b^2\\\\(x-6)^2=0\iff x-6=0\ \ \ |add\ 6\ to\ both\ sides\\\\\boxed{x=6}$

Taya2010 [7]3 years ago

4 0

$In ~~Use ... \\ x^2 - 12x = -36\rightarrow (ax^2+bx + c = 0) \\ x^2 - 12x + 36 = 0 \\ \\a = 1 \\ b = - 12 \\ c = 36 \\ \\ Delta: \\ \Delta = b^2 - 4ac \\ \Delta = (-12)^2 - 4.1.36 \\ \Delta = 144 -144 \\ \Delta = 0\\ \\ Bhaskara: \\ \\ x = \frac{-b\pm \sqrt{\Delta} }{2a} \\ \\ x = \frac{-(-12)\pm \sqrt{0} }{2.1} \\ \\ x = \frac{12\pm0}{2} 
 \\ \\ x' = \frac{12 + 0}{2} = \frac{12}{2} = 6 \\ \\ x'' = \frac{12 - 0}{2} = \frac{12}{2} = 6 \\ \\ S = \{6\}$

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Find difference 7 7/8-3 1/4

umka2103 [35]

So first convert to improper fractions
7 and 7/8=7+7/8=56/8+7/8=63/8

3 and 1/4=3+1/4=12/4+1/4=13/4

so nowe we have
63/8+13/4
convert bottom number to same
which is 8
13/4 times 2/2=26/8
now we have
63/8-26/8=37/8=4 and 5/8
answer is 4 and 5/8

8 0

3 years ago

Joan needs to estimate the size of her bedroom so that she can buy enough paint to cover the walls. Two of the walls measure 2.8

labwork [276]

The total area of the room is 37.6376 and the no. of cans required to paint the wall is 3 cans.

The measurement of two of the walls is 2.86 metres and 3.16 metre

Area of the two walls = 2(length x breadth)

Area = 2(2.86 x 3.16) = 18.0752 m²

The measurement of the other two walls is 2.86 metres and 3.42 metres

Area of the two walls = 2(length × breadth)

Area = 2(2.86 × 3.42) = 19.5624 m²

Total area = 18.0752 + 19.5624 = 37.6376 m²