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2 answers:
Step-by-step explanation:
we know that,
- sum of interior angle of triangle is 180°
Now,
In ∆QSO,
∠Q + ∠S + ∠O = 180°
35° + 30° + ∠O = 180°
∠O = 180° - 65°
<h3>∠O = 115°</h3>Now,
we know that,
- sum of all angles in a straight line is 180°
∠SOQ + ∠SOR = 180°
115° + ∠SOR = 180°
∠SOR = 180° - 115°
<h3>∠SOR = 65°</h3>Now,
In ∆RTO,
∠R + ∠T + ∠O = 180°
35° + ∠T + 65° = 180°
∠T = 180° - 100°
<h3>∠T = 80°</h3>Now,
∠T + ∠x = 180°
80° + ∠x = 180°
∠x = 180° - 80°
<h3>∠x = 100°</h3>Therefore,
Option D is correct ✔.
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Answer:
<h2> 112.3 square units</h2>Step-by-step explanation:
Find the sketch of the triangle attached.
Area of the triangle =
Given PQ = 20, PR = 12 and ∠QPR = 68°
Area of the triangle = 1/2 * 20 * 12 * sin68°
Area of the triangle = 120sin68°
Area of the triangle = 112.26 square units
Area of the triangle ≈ 112.3 square units (to the nearest tenth of a square unit)
