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Elena-2011 [213]
3 years ago
12

How do you calculate the volume of a cone when given the height and diameter?

Mathematics
2 answers:
Umnica [9.8K]3 years ago
7 0
That will be radius * radius theeeeeen multiply it on the height 
ioda3 years ago
4 0

<span>Find the radius.
</span>
Use the radius to find the area of the base circle. 

Find the height of the cone

Multiply the area of the base by the height of the cone.<span> 
</span><span>
Divide the product by three.
</span>

Hope this helps you!
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Joshua went to the hardware store and bought 4 yellow ropes. The total
shusha [124]

Answer:

15.55m

Step-by-step explanation:

<u>62</u><u>.</u><u>2</u>

4

= 15.55m

Therefore, each rope is 15.55m

5 0
3 years ago
Can a number be both rational and irrational
natulia [17]

A rational number is a number which can be expressed as a fraction whose numerator and denominator are both integers and whose denominator is not equal to zero. Rational numbers include all integers, fractions, mixed numbers, and some decimal numbers.

 

Note : All terminating and repeating decimal numbers are rational numbers because those numbers can be expressed as a fraction. On the other hand, a non repeating number and non terminating decimal, like square root of 2, is an irrational number. 

5 0
3 years ago
Read 2 more answers
I need help I'm stuck on this
ddd [48]

a) The length of p is 21.4 cm

b) The measure of angle P is 45.6°

<h3>Trigonometry </h3>

From the question, we are to determine the length of p

From the <em>Pythagorean theorem</em>, we can write that

30² = 21² + p²

p² = 30² - 21²

p² = 900 - 441

p² = 459

p = √459

p = 21.4 cm

∴ The length of p is 21.4 cm

b)

Measure of angle P

Using SOH CAH TOA

cos P= \frac{21}{30}

cos P = 0.7

P = cos⁻¹(0.7)

P = 45.6°

Hence, the measure of angle P is 45.6°

Learn more on Trigonometry here: brainly.com/question/17831932

#SPJ1

5 0
1 year ago
Recall that in a 30 – 60 – 90 triangle, if the shortest leg measures x units, then the longer leg measures xStartRoot 3 EndRoot
Brums [2.3K]

The area of the shaded region is  \rm (150\sqrt{3} \ - 75\pi ) \ feet^2 option first is correct.

It is given that a circle is inscribed in a regular hexagon with sides of 10 feet.

It is required to find the shaded area (missing data is attached shown in the picture).

<h3>What is a circle?</h3>

It is defined as the combination of points that and every point has an equal distance from a fixed point ( called the center of a circle).

We have a hexagon with a side length of 10 feet.

We know the area of the hexagon is given by:

\rm A = \frac{3\sqrt{3} }{2} a^2  where a is the side length.

\rm A = \frac{3\sqrt{3} }{2} 10^2 ⇒ 150\sqrt{3} \rm feet^2

We have the shortest length = x feet and from the figure:

2x = 10

x = 5 feet

The radius of the circle r = longer leg

\rm r = x\sqrt{3} \Rightarrow 5\sqrt{3} feet

The area of the circle a = \pi r^2  ⇒ \pi (5\sqrt{3} )^2 \Rightarrow 75\pi \ \rm feet^2  

The area of the shaded region = A - a

\rm =(150\sqrt{3} \ - 75\pi ) \ feet^2

Thus, the area of the shaded region is  \rm (150\sqrt{3} \ - 75\pi ) \ feet^2

Learn more about circle here:

brainly.com/question/11833983

7 0
2 years ago
What is the y-value of the vertex of the function f(x)=-(x-3)(x+11)
lutik1710 [3]

so, this is a quadratic equation, meaning two solutions, and we have a factored form of it, meaning you can get the solutions by simply zeroing out the f(x).

\bf \stackrel{f(x)}{0}=-(x-3)(x+11)\implies 0=(x-3)(x+11)\implies x= \begin{cases} 3\\ -11 \end{cases} \\\\\\ \boxed{-11}\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}-4\stackrel{\textit{\large 7 units}}{\rule[0.35em]{10em}{0.25pt}}\boxed{3}

so the zeros/solutions are at x = 3 and x = -11, now, bearing in mind the vertex will be half-way between those two, checking the number line, that midpoint will be at x = -4, so the vertex is right there, well, what's f(x) when x = -4?

\bf f(-4)=-(-4-3)(-4+11)\implies f(-4)=7(7)\implies f(-4)=49 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{vertex}{(-4~~,~~49)}~\hfill

7 0
3 years ago
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