Answer: Its A, Your Welcome.
Step-by-step explanation:
Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
Answer:
a. 
b. 
c. 
d. -6t - 5
Step-by-step explanation:
When a number has the same variable as another, you can add or subtract them
So for the first one, you can do
(But don't forget the 
!)
So it is:
Continue this process for the rest of them
Answer:
1811.6
Step-by-step explanation:
647x28
18116
move once to the left bc of the point in 64.7
1811.6
Answer:
<h3> 10,450</h3>
Step-by-step explanation:
21-13=8 and 29-21=8
So this is aritmetic series where a₁ = 13, and r = 8
Sum of the first n terms:
