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Anettt [7]
3 years ago
8

Solve. −3/5x +1/5 > 7/20

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
5 0

Answer:

x< -1/4

Step-by-step explanation:

Reika [66]3 years ago
3 0
-3/5x + 1/5 > 7/20
-3/5x > 7/20 - 1/5
-3/5x > 7/20 - 4/20
-3/5x > 3/20
x < 3/20 * - 5/3
x < -15/60 reduces to -1/4

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Write 6 x 10 x 10 x 10 x 10 with an exponent
Travka [436]
I believe it would be 6(10^4)
3 0
3 years ago
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Caleb and Mike both score the same amount of points in a game. Caleb has fifteen less than the total number of points. Mike has
elena-s [515]
Answer:
129 points
Step-by-step explanation:
Let L and C represent the scores of Luke and Caleb, respectively.
L = 2C -15 . . . . . Luke scored 15 less than twice the number Caleb did
L +C = 201 . . . . . they scored 201 points altogether
Add twice the second equation to the first:
2(L +C) + (L) = 2(201) + (2C -15)
3L +2C = 387 +2C . . . . simplify
3L = 387 . . . . . . . . . . . . .subtract 2C
L = 387/3 = 129 . . . . . . .divide by 3
Luke scored 129 points.
3 0
3 years ago
Calculate the area of a circle with radius of 2 cm
Mariulka [41]
A = pi × r²

3.14 x 2²

3.14 x 4 

A = 12.56636 ≈ 12.56
 
hopefully this helps u and if u know the formula to solve it, it is super easy

6 0
3 years ago
Read 2 more answers
The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m
photoshop1234 [79]

Answer: 0.1353

Step-by-step explanation:

Given : The mean of failures =  0.025 per hour.

Then  for 8 hours , the mean of failures = \lambda=8\times0.25=2 per eight hours.

Let X be the number of failures.

The formula to calculate the Poisson distribution is given by :_

P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}

Now, the probability that the instrument does not fail in an 8-hour shift :-

P(X=0)=\dfrac{e^{-2}2^0}{0!}=0.1353352\approx0.1353

Hence, the the probability that the instrument does not fail in an 8-hour shift = 0.1353

7 0
3 years ago
A fruit company delivers its fruit in two types of boxes: large and small. a delivery of 5 large boxes and 3 small boxes has a t
Hoochie [10]
Let's let the weight of a large box be L, and the weight of a small box be S.

We know that 5 large boxes and 3 small boxes is 120kg, so:
5L + 3S = 120

We also know that 7 large boxes and 9 small boxes is 234kg, so:
7L + 9S = 234

You can multiply the first equation by 3 to get:
15L + 9S = 360

See how now both equations have 9S? We can now subtract one from the other:
(15L+9S) - (7L+9S) = 360-234
8L = 126
L = 15.75

Now sub this value back into an equation:
(5x15.75) + 3S = 120
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Double check these values
(7x15.75) + (9x13.75)
= 110.25 + 123.75
=234, which is consistent with above.

So a large box is 15.75kg, and a small box is 13.75kg.

Hope this helped
5 0
3 years ago
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