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Eva8 [605]
3 years ago
14

A set of numbers is shown:

Mathematics
1 answer:
Studentka2010 [4]3 years ago
6 0
3x + 3 > or equal to 21
3x > -3 +21
3x>18
x> 18/3
x> or equal to = 6
3(6) + 3 > 21
18 + 3 > 21
21> 21
So remember greater than or equal to

6 for x is equal to
12 for x is greater than
3(12)

18 for x is greater than 21. 3(18)

Answer is (6,12,18)

3(2.8) = 8.4 + 3 is only 11.4 < 21
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3y=12x+6 in slope-intercept form
tresset_1 [31]

Answer:

\displaystyle y = 4x + 2

Step-by-step explanation:

\displaystyle \frac{3y}{3} = \frac{4x + 12}{3} \\ \\ y = 4x + 2

I am joyous to assist you anytime.

8 0
3 years ago
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
3 years ago
Find the future value and interest earned if $8906.54 is invested for 9 years at 6% compounded continuously 
dalvyx [7]
To find the future value the formula is
A=p e^rt
A future value?
P present value 8906.54
R interest rate 0.06
T time 9 years
E constant
A=8,906.54×e^(0.06×9)
A=15,283.68

To find the interest earned the formula is
I=A-p
I=15,283.68−8,906.54
I=6,377.14
4 0
3 years ago
. IF F(x) = 2(x-3) + 4, what is F(-2)?
Virty [35]
F(x) = 2(x-3) + 4
F(-2) = 2(-2-3) + 4
F(-2) = 2(-5) + 4
F(-2) = -10 + 4
F(-2) = -6

Hope this helps
8 0
3 years ago
Read 2 more answers
Someone please help me on number 30. Thank you
timurjin [86]

8.9-3.3j=-2.2j+2.3
add 3.3j to both sides
8.9=1.1j+2.3
subtract 2.3 from both sides
6.6=1.1j
divide both sides by 1.1
6=j
7 0
3 years ago
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