Answer:
A quick way to calculate upper and lower bands is to halve the degree of accuracy specified, then add this to the rounded value for the upper bound and subtract it from the rounded value for the lower bound.
<h2>Hey mate,</h2><h3>I have attached the answer below</h3><h3>Hope it will help you...</h3>
(cube root of 5) * sqrt(5)
--------------------------------- = ?
(cube root of 5^5)
This becomes easier if we switch to fractional exponents:
5^(1/3) * 5^(1/2) 5^(1/3 + 1/2) 5^(5/6)
------------------------ = --------------------- = ------------- = 5^[5/6 - 5/3]
[ 5^5 ]^(1/3) 5^(5/3) 5^(5/3)
Note that 5/6 - 5/3 = 5/6 - 10/6 = -5/6.
1
Thus, 5^[5/6 - 5/3] = 5^(-5/6) = --------------
5^(5/6)
That's the correct answer. But if you want to remove the fractional exponent from the denominator, do this:
1 5^(1/6) 5^(1/6)
---------- * ------------- = -------------- (ANSWER)
5^(5/6) 5^(1/6) 5
Answer:
x = 25 and <A = 148 degrees
Step-by-step explanation:
Basically it's asking you to find the value of x for both of those equations, x must be the same for both
6x - 2 = 4x + 48
Answer:
Step-by-step explanation:
Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P and verify if it is the closest to A or there is another one of the line
Having the point P(3,5) substitue x to verify y
y=2*(3)-1=6-1=5 (3,5)
Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found

and we found the distance PQ and QA
;
, 
be the APQ triangle we must find <APQ through the cosine law (graph 2).