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olga nikolaevna [1]
3 years ago
6

$ 12 Select the box in each rowia WA 6

Mathematics
1 answer:
scoundrel [369]3 years ago
5 0
I’m sorry, but could you provide more details to your question?
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What is the expression (cscx+cotx)^2 the same as?
Nataly_w [17]
<span>c)1 + 2cot^2x + 2cscx cotx

because cosc^2x=1+cot^2x</span>
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3 years ago
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Do ya'll have any suggestions about this?
Elanso [62]

Hello, I know your situation. Ask them for another chance. Ask them to forgive you and you will do your homework. Say "If this continues, then I accept full consiquinses". Make sure you ACTUALLY stick to what you say. Now, to the focusing part... Try to do ATLEAST 2 lessons for each class. (depends what school you are attending) If it seems that you are finishing too fast (less than 2 hrs), then do more homework until your homework hours fits you.

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3 years ago
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Use the divergence theorem to find the outward flux of the vector field F(xyz)= 4x^2 i + 4y^2 j + 3z^2 k across the boundary of
Pavel [41]

\vec F(x,y,z)=4x^2\,\vec\imath+4y^2\,\vec\jmath+3z^2\,\vec k\implies\nabla\cdot\vec F=8x+8y+6z

Let S be the surface of the rectangular prism bounded by the planes x=0, x=a, y=0, y=b, z=0, and z=c. By the divergence theorem, the integral of \vec F over S is given by the integral of \nabla\cdot\vec F over the interior of S (call it R):

\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\iiint_R(\nabla\cdot\vec F)\,\mathrm dV

=\displaystyle\int_0^c\int_0^b\int_0^a(8x+8y+6z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=\boxed{abc(4a+4b+3c)}

5 0
3 years ago
What is 8c + 10b ÷ 7a if c = 7, b = 12, and a = 5 Please give a full and good explanation for a brainliest...​
PolarNik [594]

Answer:

141  5/7

Step-by-step explanation:

8c + 10b ÷ 7a

Let c = 7, b = 12, and a = 5

8*7 + 10*12 ÷ 7*5

Multiply and divide from left to right

56+120 ÷7*5

56+ 600/7

Get a common denominator

392/7 + 600/7

992/7

Change from an improper fraction to a mixed number

141  5/7

8 0
3 years ago
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These rational expressions all have the same denominator write the sum of their numerators over the common denominator 2x+1 + x
ale4655 [162]

So if all same you just simplify  The top :  2x+1+x+4  2x+x+1+4 3x+5  The bottom all same just use one .x-3  3x+5/x-3

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