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LuckyWell [14K]
3 years ago
6

12/7=k/8 slove for k

Mathematics
2 answers:
Tresset [83]3 years ago
8 0

k=13.7 or in fraction

Step-by-step explanation:

7k=12x8

7k=96

k=13.7

12345 [234]3 years ago
7 0

Answer:

k = 96/7

Step-by-step explanation:

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I really need help asap!!
Firdavs [7]

Given:

A figure of a parallelogram.

The vertex angles are (12b+8)^\circ,(5b+2)^\circ,2a^\circ.

To find:

The values of a and b.

Solution:

We know that the pairs of consecutive angles of a parallelogram are supplementary angles. It mean their sum is 180 degrees.

(12b+8)^\circ+(5b+2)^\circ=180^\circ       (Supplementary angles)

(17b+10)^\circ=180^\circ

17b+10=180

Subtract 10 from both sides.

17b=180-10

17b=170

Divide both sides by 17.

b=\dfrac{170}{17}

b=10

Now,

(5b+2)^\circ=(5(10)+2)^\circ

(5b+2)^\circ=(50+2)^\circ

(5b+2)^\circ=52^\circ

And,

(5b+2)^\circ+2a^\circ=180^\circ       (Supplementary angles)

52^\circ+2a^\circ=180^\circ

2a^\circ=180^\circ-52^\circ

2a^\circ=128^\circ

Divide both sides by 2.

a^\circ=\dfrac{128^\circ}{2}

a^\circ=64^\circ

a=64

Therefore, the value of a is 64 and the value of b is 10.

5 0
3 years ago
13. Find the range of the function on the graph<br> below.
aliina [53]

Range is ] -20 , -10 [

both points are disclude according to the empty circle

4 0
1 year ago
6 red marbles out of 36 marbles
Andreyy89

Answer:

1/6

Step-by-step explanation:

P(red) = red/total

             =6/36

             =1/6

6 0
3 years ago
Solve the inequality.<br><br> y−5≥8
mixas84 [53]

Answer:

Y is less than or equal to 13

Step-by-step explanation:

3 0
3 years ago
There are 5 cocoa pods in a bag.
Virty [35]

Answer:

416 g

Step-by-step explanation:

The mean is calculated as

mean = \frac{sum}{count} , then

\frac{sum}{5} = 398 ( multiply both sides by 5 )

sum of 5 pods = 1990 g

let x be the weight of the sixth pod , then

\frac{1990+x}{6} = 401 ( multiply both sides by 6 )

1990 + x = 2406 ( subtract 1990 from both sides )

x = 416

That is the weight of the sixth pod is 416 g

6 0
2 years ago
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