Question

If the pressure at a depth of 8 ft below the surface of a stagnant fluid is 3.5 psi, what will the pressure of the liquid be at a depth of 48 ft below the surface?

Answer 1

Answer : The pressure of the liquid at depth of 48 ft below the surface of fluid is, 21 psi.

Explanation : Given,

The pressure of the liquid at depth 8 ft = 3.5 psi

Now we have to calculate the pressure of the liquid at depth 28 ft.

According to the question,

As, the depth of 8 ft below the surface of a stagnant fluid has pressure = 3.5 psi

So, the depth of 48 ft below the surface of a stagnant fluid has pressure = $\frac{3.5\text{ psi}}{8\text{ ft}}\times 48\text{ ft}=21\text{ psi}$

Therefore, the pressure of the liquid at depth of 48 ft below the surface of fluid is, 21 psi.