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NikAS [45]
3 years ago
15

Question 4 to make a 0.500 m solution, one could take 0.500 moles of solute and add 1.00 l of solvent. enough solvent to make 1.

00 kg of solution. enough solvent to make 1.00 l of solution. 1.00 kg of solvent.
Chemistry
2 answers:
stealth61 [152]3 years ago
7 0
The answer is enough solvent to make 1.00 L of solution. Since molarity is the number of moles of solute in one liter of solution, adding 0.500 mole solute to one liter solvent might not result to a solution with one liter total volume. Less than one liter solvent is first added to dissolve 0.500 mole solute and then the solution is carefully filled with more solvent until the solution reaches to one liter total volume. Hence, the resulting solution is a 0.500M concentration.
poizon [28]3 years ago
7 0

Enough solvent to make 1.00 L of solution.

<h3>Further explanation</h3>

<u>The Problem</u>

To make a 0.500 M solution, one could take 0.500 moles of solute and add?

<u>The Process</u>

  • A solution consists of a solute and a solvent.
  • There are several ways to express the concentration of a solution, one of which is molarity. Molarity is also known as molar concentration with the symbol unit M or molar or mol/L.
  • The molarity (M) of a solution is calculated by taking the moles of solute and divided by the number of liters of solution.

\boxed{ \ molarity = \frac{moles \ of \ solute}{liters \ of \ solution} \ }

Therefore, to make a 0.500 M solution, we could take 0.500 moles of solute and add enough solvent to make 1.00 L of solution.

\boxed{ \ \frac{0.500 \ moles}{1.00 \ L \ of \ solution} = 0.500 \ M \ }

- - - - - - - - - -

Notes

  • The concentration of the solution can also be expressed in molality.
  • The symbol unit of molality is m or molal or mol/kg.
  • The molality of a solution is calculated by taking the moles of solute and dividing by the kilograms of solvent.

\boxed{ \ molality = \frac{moles \ of \ solute}{kilograms \ of \ solvent} \ }

As an example, to make a 0.500 m solution we could take 0.500 moles of solute and add 1.00 kg of solvent.

<h3>Learn more</h3>
  1. How many liters of the  50% solution and how many liters of the  90%  solution will be used? brainly.com/question/13034221
  2. The molality and mole fraction of water brainly.com/question/10861444
  3. How much of these solutions he needs to drain and replace with 70% acid solution to obtain 100g of 60% acid solution brainly.com/question/7596086
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Explanation:

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