Question

The accepted density of copper is 8.96 g/mL. Calculate the percent error of a student’s measurement which resulted in a density of 8.86 g/mL.

Answer 1

Answer:

The answer is 1.12 %

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\%$

From the question

actual density = 8.96 g/mL

error = 8.96 - 8.86 = 0.1

We have

$p(\%) = \frac{0.1}{8.96} \times 100 \\ = 1.1160714...$

We have the final answer as

1.12 %

Hope this helps you