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A sports car has an average acceleration of 5.81 m/s2. How long does it take for the car to reach 60.0 mi/h, if it starts from r

Aleks04 [339]

Answer:

4.617 s

Explanation:

The speed of 60 mi/h can be converted to m/s:

(60 mi/h) × (1609.344 m/mi) × (1 h)/(3600 s) = 26.8244 m/s

The relationship between speed and acceleration is ...

v = at

t = v/a = (26.8244 m/s)/(5.81 m/s²) ≈ 4.617 s

It will take the car 4.617 seconds to reach 60 mi/h starting from rest.

5 0

3 years ago

Read 2 more answers

Is it possible for an inverted pyramid to exist, like the one show here? Explain your answer.

Korvikt [17]

Answer:

Not possible, if we talk about real pyramids

Explanation:

There is no image shown in the question statement. However if we talk about the pyramids as we find them in Egypt, we cannot get a stable inverted pyramid because of the difficulty in terms of balancing it from its centre of mass. In theory one might balance the forces, but in actual, to balance all the load of the structure just on a point is extremely difficult.

However, the term inverted pyramid can be found in ecological system and also used as metaphors in English literature

5 0

3 years ago

An astronaut weighs 8.00 × 102 newtons on the sur- face of Earth. What is the weight of the astronaut 6.37 × 106 meters above th

kolbaska11 [484]

Answer:

$mg=200.4 N$ .

Explanation:

This problem can be solved using Newton's law of universal gravitation: $F=G\frac{m_{1}m_{2}}{r^{2}}$ ,

where F is the gravitational force between two masses $m_{1}$ and $m_{2}$ , $r$ is the distance between the masses (their center of mass), and $G=6.674*10^{-11}(m^{3}kg^{-1}s^{-2})$ is the gravitational constant.

We know the weight of the astronout on the surface, with this we can find his mass. Letting $w_{s}$ be the weight on the surface:

$w_{s}=mg$ ,

$mg=8*10^{2}$ ,

$m=(8*10^{2})/g$ ,

since we now that $g=9.8m/s^{2}$ we get that the mass is

$m=81.6kg$ .

Now we can use Newton's law of universal gravitation

$F=G\frac{Mm}{r^{2}}$ ,

where $m$ is the mass of the astronaut and $M$ is the mass of the earth. From Newton's second law we know that

$F=ma$ ,

in this case the acceleration is the gravity so

$F=mg$ , (becarefull, gravity at this point is no longer $9.8m/s^{2}$ because we are not in the surface anymore)

and this get us to

$mg=G\frac{Mm}{r^{2}}$ , where $mg$ is his new weight.

We need to remember that the mass of the earth is $M=5.972*10^{24}kg$ and its radius is $6.37*10^{6}m$ .

The total distance between the astronaut and the earth is

$r=(6.37*10^{6}+6.37*10^{6})=2(6.37*10^{6})=12.74*10^{6}$ meters.

Now we can compute his weigh:

$mg=G\frac{Mm}{r^{2}}$ ,

$mg=(6.674*10^{-11})\frac{(5.972*10^{24})(81.6)}{(12.74*10^{6})^{2}}$ ,

$mg=200.4 N$ .

5 0

3 years ago

Assume that the pictured magnet is being moved into the solenoid. If the polarity of the magnet is reversed and then moved into

KonstantinChe [14]

Answer:

The direction of induced emf is revered and hence the direction of the induced current.

Explanation:

If the polarity of the magnet is reversed, the direction if the field lines through the solenoid is also reversed, which according to Faraday's law means

$\varepsilon =N\dfrac{d\Phi}{dt} \rightarrow -N\dfrac{d\Phi}{dt}$