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3 years ago

7

A student is playing with a pendulum. He gives the ball a push and watches the ball as it swings. After a while, the ball stops

swinging.Why does the ball stop swinging?

1 answer:

julia-pushkina [17]3 years ago

4 0

A because it’s not good

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What is the current of a 10 Ohm resistor attached to a 9 volt battery?

Gnom [1K]

I'm giving you a general formula , its called ohm law it states that <span>electric current is proportional to voltage and inversely proportional to resistance

if V=voltage associated with the battery
R=resistance , I=current then
</span> $\boxed{V=I*R}$ <span>
</span>

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3 years ago

A wave created by shaking a rope up and down is called a.

Sidana [21]

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2 years ago

Creativity is always discouraged in scientific endeavors.

shepuryov [24]

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3 years ago

Read 2 more answers

Two marbles, one twice as heavy as the other, are dropped to the ground from the roof of a building. Just before hitting the gro

Andreyy89

Answer:

B. twice as much kinetic energy

Explanation:

Lets take the mass of the first marble =2 m

the mass of the second marble = m

We know that velocity of particle does not depends on their mass that is the velocity of both mass will be same after dropping from the roof.

We know that kinetic energy of a mass is given as

$KE=\dfrac{1}{2}Mv^2$

Kinetic energy for heavier mass

$KE=\dfrac{1}{2}\times 2m\times V^2$

Kinetic energy for light mass

$KE'=\dfrac{1}{2}\times m\times V^2$

KE=2 KE '

Form above two equation we can say that ,the kinetic energy for the heavier mass is twice the lighter mass.

Therefore the answer will be B.

7 0

3 years ago

A man does 4,475 J of work in the process of pushing his 2.50 103 kg truck from rest to a speed of v, over a distance of 26.0 m.

Tcecarenko [31]

Answer:

a) 1.89 m/s b) 172.1 N

Explanation:

a)

Applying the work-energy theorem, if we can neglect the friction between truck and road, the total change in kinetic energy must be equal to the work done by the external forces.
This work, is just 4,475 J.
So we can write the following equation:

$\Delta K = \frac{1}{2} * m*v^{2} = 4,475 J$

where m= mass of the truck = 2.5*10³ kg.
So, we can find the speed v, as follows:

$v =\sqrt{\frac{2*W}{m}} =\sqrt{\frac{2*4,475J}{2.5e3kg} } = 1.89 m/s$

b)

The work done by the man, is just the horizontal force applied, times the displacement produced by the force horizontally:

$W = F*d$

We can solve for F, as follows:

$F = \frac{W}{d} = \frac{4,475 J}{26.0m} = 172.1 N$

4 0

3 years ago