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german
3 years ago
12

Assume that the pictured magnet is being moved into the solenoid. If the polarity of the magnet is reversed and then moved into

the solenoid, what happens? *
Physics
1 answer:
KonstantinChe [14]3 years ago
7 0

Answer:

The direction of induced emf is revered and hence the direction of the induced current.

Explanation:

If the polarity of the magnet is reversed, the direction if the field lines through the solenoid is also reversed, which according to Faraday's law means

\varepsilon  =N\dfrac{d\Phi}{dt} \rightarrow -N\dfrac{d\Phi}{dt}

in other words, the direction of the magnetic flux is revered, and therefore, the direction of the induced emf is also revered.

Furthermore, according to Ohm's law

I = \dfrac{\varepsilon}{R}

which tells us that if the induced emf changes sign <em>(is reversed)</em>

I = -\dfrac{\varepsilon}{R}

the direction of the induced current is also reversed.

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The loudness of a sound is the waves amplitude <br><br><br><br> True or false
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Answer:

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Which statement best describes the relationship between an object's density and its index of refraction? as the optical density
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Which of these statements is correct about Newton's first law of motion?
nexus9112 [7]

Answer:

Answer D: It describes the relationship between motion and force.

Explanation:

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4 0
3 years ago
A string is stretched to a length of 308 cm and both ends are fixed. If the density of the string is 0.023 g/cm, and its tension
soldi70 [24.7K]

Answer:

Frquency=3,994Hz

Explanation:

Tension =967N

Density of string (μ)=0.023g/cm

Length of the stretched spring=308cm

Fundamental frequency for nth harmonic :

Fn=n/2L(√T/μ)

Substituting the given values to find the frequency :

f1=1/2(308cm) *(0.01m/1cm)[(√967N)/(0.023g/cm)(0.1kg)/(0.1kg/m)/(1g/cm)]

=6.16m[(√967N)/0.0023kg/m)]

=3,994.20Hz

Approximately,

The frequency will be =3,994Hz

7 0
3 years ago
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