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olga2289 [7]
3 years ago
6

Ganymede is one of the many moons of jupiter. it is nearly a sperical in shape. it is larger than the planet mercury and slightl

y smaller than the planet mars. if it is so large compared with the bodies around it, why is it called a moon and not a planet?
Physics
1 answer:
Evgen [1.6K]3 years ago
7 0
Ganymede is the largest satellite in our solar system. It is larger
than Mercury and Pluto, and three-quarters the size of Mars.

==> If Ganymede orbited the sun instead of orbiting Jupiter, it would
easily be classified as a planet.
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A 0.140-kg baseball is dropped from rest. It has a speed of 1.20 m/s just before it hits the ground, and it rebounds with an upw
irga5000 [103]

Answer:

22 N upward

Explanation:

From the question,

Applying newton's second law of motion

F = m(v-u)/t....................... Equation 1

Where F = Average force exerted by the ground on the ball, m = mass of the baseball, v = final velocity, u = initial velocity, t = time of contact

Note: Let upward be negative and downward be positive

Given: m = 0.14 kg, v = -1.00 m/s, u = 1.2 m/s, t = 0.014 s

Substitute into equation 1

F = 0.14(-1-1.2)/0.014

F = 0.14(-2.2)/0.014

F = 10(-2.2)

F = -22 N

Note the negative sign shows that the force act upward

6 0
3 years ago
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inysia [295]

Answer:

3.1 m/s

Explanation:

First, find the time it takes for the cat to land.  Take down to be positive.

Given:

Δy = 0.61 m

v₀ = 0 m/s

a = 9.81 m/s²

Find: t

Δy = v₀ t + ½ at²

(0.61 m) = (0 m/s) t + ½ (9.81 m/s²) t²

t = 0.353 s

Now find the horizontal velocity needed to travel 1.1 m in that time.

Given:

Δx = 1.1 m

a = 0 m/s²

t = 0.353 s

Find: v₀

Δx = v₀ t + ½ at²

(1.1 m) = v₀ (0.353 s) + ½ (0 m/s²) (0.353 s)²

v₀ = 3.1 m/s

3 0
3 years ago
Which state of matter is the least compressible
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7 0
3 years ago
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Answer:

describe three different ways to change your velocity when youre riding a bike?

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3 years ago
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On a frictionless horizontal air table, puck A (with mass 0.252 kg ) is moving toward puck B (with mass 0.374 kg ), which is ini
geniusboy [140]

As we know that kinetic energy is given as

KE = \frac{1}{2}mv^2

Here we can find the initial speed of puck A by momentum conservation

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

0.252\times v + 0 = 0.252\times (-0.115) + 0.374\times ( 0.650)

v = 0.850 m/s

now here we will have initial kinetic energy of the mass is given as

KE_i = \frac{1}{2}m_1v_1^2

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KE_f = \frac{1}{2}(0.252)(-0.115)^2 + \frac{1}{2}(0.374)(0.650^2)

KE_f = 0.081 J

now loss of energy is given as

KE_i - KE_f = 0.091 - 0.081 = 0.010 J

6 0
3 years ago
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