To solve this problem we will apply the concepts related to energy conservation. Here we will use the conservation between the potential gravitational energy and the kinetic energy to determine the velocity of this escape. The gravitational potential energy can be expressed as,
The kinetic energy can be written as,
Where,
Gravitational Universal Constant
Mass of Earth
Height
Radius of Earth
From the conservation of energy:
Rearranging to find the velocity,
Escape velocity at a certain height from the earth
If the height of the satellite from the earth is h, then the total distance would be the radius of the earth and the eight,
Replacing the values we have that
Therefore the escape velocity is 3.6km/s
B.temperature is an indirect measurement of the heat energy in a substance
Answer:
The required radius is 2.62 cm
Explanation:
Given;
magnitude of current in wire, I = 1.31 A
magnetic field strength, B = 10 µT
Applying Biot Savart equation;
where;
r is the radius of the wire
μ₀ is constant = 4π x 10⁻⁷ Tm/A
I is the current in the wire
B is the magnetic field strength
Substitute the given values and calculate the radius
Therefore, the required radius is 2.62 cm
Answer:
Explanation:
<u>Instant Velocity and Acceleration
</u>
Give the position of an object as a function of time y(x), the instant velocity can be obtained by
Where y'(x) is the first derivative of y respect to time x. The instant acceleration is given by
We are given the function for y
Note we have changed the last term to be quadratic, so the question has more sense.
The velocity is
And the acceleration is
