The temperature on the planet Mercury alternates depending

Which is the polynomial function of lowest degree

Tems11 [23]

Option D:

f(x) = x(x + 2)(x + 5)

Solution:

Given root of the polynomial functions are:

–5, –2 and 0.

If a is the root of the polynomial then the factor is (x –a).

So that, the factors of the given roots are:

(x –(–5)) = x + 5

(x –(–2)) = x + 2

(x – 0) = x

Polynomial = Product of the factors

f(x) = (x + 5)(x + 2)x

Switch the order of the factors.

f(x) = x(x + 2)(x + 5)

Option D is the correct answer.

The polynomial function of lowest degree is f(x) = x(x + 2)(x + 5).

3 0

3 years ago

Three more than twice a number x is seven,

Zanzabum

Answer:

2(x-7) + 3 = 9

2x - 14 = 6

2x = 20

x = 10

Step-by-step explanation:

6 0

3 years ago

Please. help me solve. this !!!!! very hard. , explain. please

umka2103 [35]

102
the angles are alternate so they add up to 180
180-78=102

hope this helps :)
if you need me to explain more just let me know :)

6 0

3 years ago

There were 29 students available for the woodwind section of the school orchestra. 11 students could play the flute, 15 could pl

Dafna11 [192]

Answer:

a. The number of students who can play all three instruments = 2 students

b. The number of students who can play only the saxophone is 0

c. The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only one of the clarinet, saxophone, or flute = 4

Step-by-step explanation:

The total number of students available = 29

The number of students that can play flute = 11 students

The number of students that can play clarinet = 15 students

The number of students that can play saxophone = 12 students

The number of students that can play flute and saxophone = 4 students

The number of students that can play flute and clarinet = 4 students

The number of students that can play clarinet and saxophone = 6 students

Let the number of students who could play flute = n(F) = 11

The number of students who could play clarinet = n(C) = 15

The number of students who could play saxophone = n(S) = 12

We have;

a. Total = n(F) + n(C) + n(S) - n(F∩C) - n(F∩S) - n(C∩S) + n(F∩C∩S) + n(non)

Therefore, we have;

29 = 11 + 15 + 12 - 4 - 4 - 6 + n(F∩C∩S) + 3

29 = 24 + n(F∩C∩S) + 3

n(F∩C∩S) = 29 - (24 + 3) = 2

The number of students who can play all = 2

b. The number of students who can play only the saxophone = n(S) - n(F∩S) - n(C∩S) - n(F∩C∩S)

The number of students who can play only the saxophone = 12 - 4 - 6 - 2 = 0

The number of students who can play only the saxophone = 0

c. The number of students who can play the saxophone and the clarinet but not the flute = n(C∩S) - n(F∩C∩S) = 6 - 2 = 4

The number of students who can play the saxophone and the clarinet but not the flute = 4 students

d. The number of students who can play only the saxophone = 0

The number of students who can play only the clarinet = n(C) - n(F∩C) - n(C∩S) - n(F∩C∩S) = 15 - 4 - 6 - 2 = 3

The number of students who can play only the clarinet = 3

The number of students who can play only the flute = n(F) - n(F∩C) - n(F∩S) - n(F∩C∩S) = 11 - 4 - 4 - 2 = 1

The number of students who can play only the flute = 1

Therefore, the number of students who can play only one of the clarinet, saxophone, or flute = 1 + 3 + 0 = 4

The number of students who can play only one of the clarinet, saxophone, or flute = 4.

6 0

4 years ago

What is the measure of arc AC?

8_murik_8 [283]

If Im not mistaken, the answer should be d because if you add all the degrees up, then you would get 222. And if you subtract 360 from 222 you get 138. I hope this helps. :)

7 0

3 years ago