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SVETLANKA909090 [29]
3 years ago
5

Round 62,981 to the nearest thousand.

Mathematics
2 answers:
olga2289 [7]3 years ago
7 0

Answer:

63,000

Step-by-step explanation:

When 981 is rounded to the nearest thousand, it is equal to 1,000. Add this to the remaining number, 62,000, and voila! you get it!

62,000 + 1,000 = 63,000

If you want this explained further, please just let me know!

Thanks!

alexgriva [62]3 years ago
6 0
In 62,981 the two is in the thousands place and the 9 is the number that determines if the two will remain a two or if it will go to three. The nine rounds to 10 so the 2 will be a three will the other numbers behind it turn into a 0. The answer is 63,000
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Help !!!! Match the written mathematical operation to the equivalent symbolic form
Burka [1]

Answer:

The matched pairs are:

(A, 4), (B, 1), (C, 2) and (D, 3)

Step-by-step explanation:

The complete question is:

Match each description of an algebraic expression with the symbolic form of that expression :

A. 2 terms; variables = x and y

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D. 3 terms; variables = x and y; constant = 2

1. x - 2y + 3

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3. 4.5x + 2 - 3y

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Solution:

A. 2 terms; variables = x and y  ⇒ 4. 4.5y - 2x

B. 3 terms; variables = x and y; constant = 3  ⇒ 1. x - 2y + 3

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3 years ago
Express the
Gnesinka [82]
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3 years ago
The population of California was 29.76 million in 1990 and 33.87 million in 2000. Use the model found in part a (f(x) =29.76(1.0
NeTakaya

Answer:

The average rate of change from 1990 to 1991 is 0.387 \:\frac{million}{years}

The average rate of change from 2000 to 2001 is 0.440 \:\frac{million}{years}

Step-by-step explanation:

The average rate of change of function f(x) over the interval a\leq x\leq b is given by

\frac{f(b)-f(a)}{b-a}

It is a measure of how much the function changed per unit, on average, over that interval.

From the information given:

  • The function that models the population t years after 1990 is f(t) =29.76(1.013)^t
  • The year 1990 is t = 0 and the year 2000 is t = 10.

1. The average rate of change from 1990 to 1991 is:

The interval is 0\leq x\leq 1

\frac{29.76(1.013)^1-29.76(1.013)^0}{1-0}\\\\\frac{1.013^1\cdot \:29.76-1\cdot \:29.76}{1-0}\\\\\frac{0.38688}{1-0}\\\\0.387 \:\frac{million}{years}

2. The average rate of change from 2000 to 2001 is

The interval is 10\leq x\leq 11

\frac{29.76(1.013)^{11}-29.76(1.013)^{10}}{11-10}\\\\\frac{0.44022}{11-10}\\\\0.440 \:\frac{million}{years}

8 0
3 years ago
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