Answer: D. 
Step-by-step explanation:
Using exponent rules an exponent to the power of a number will multiply by each other.
So the -4 and -9 will multiply.
The 6 in the numerator will now have a positive exponent of 36.

Now we can divide and when we do so the exponents will subtract from each other.
So 36 - 6 = 30
And the base of 6 does not change.
The simplified form is 
Answer:
Step-by-step explanation:
Surface area of objects with flat surfaces like this is simply the area of each surface added together, so let's get to work.
Both have 6 faces, so we will be adding six values together for each.
Container A:
Hopefully you can imagine the six different faces. It's kinda like a cereal box.
The front and back of a cereal box have the same area, as do the two sides and the top and bottom, so that makes it a little easier.
Front and Back: 28 * 36 = 1008
Sides: 36*6 = 216
Top and Bottom: 6*28 = 168
Let me know if you don't understand how I did any of that. Anyway, since there is a matching face for each we add them all together twice.
1008*2 + 216*2 + 168*2 = 2784 in^2
Container B has a similar setup, I won't write out everything like I did unless you want me to work it out with you.
2(16*12+16*22+22*12) = 1616 in^2
So since Container A has a surface area of 2784 and Container B has a surface area of 1616 it's obvious container A has a larger surface area
<span>9y+y = y(9 + 1) = 10y
answer is 10y
if </span><span>9y^2 then it should be 9y times y = 9y^2
hope it helps</span>
Hey there! :)
Answer:
The bag is cheaper because one litre is roughly $1.00, compared to the carton which is $1.99 for one litre.
Step-by-step explanation:
Given:
Bag of 4 litre milk = $3.99
Carton of 1 litre milk = $1.99
Find the price per litre for a bag of milk:

Cross multiply:
3.99 = 4x
Divide both sides by 4:
3.99/4 = x.
x = 0.9975 ≈ $1.00
Bag of 1 litre milk ≈ $1.00
Carton of 1 litre milk = $1.99
$1.00 < $1.99
Therefore, the bag is cheaper.
Answer:
a^2b(7 + 10b + 14b^2)
Use wolframalpha for math questions, or photomath!
To solve this, factor out a^2b from the expression.