The difference (I'm assuming you meant difference) between 279 and 63 is
279 - 63 = 216
so divide 432 by 216
432 / 216 = 2
so the answer is 2
Answer:
Step-by-step explanation:
just take 8.5% of 28,020 off for ever year until you get to 2030.
8.5% is 2381.70
Take 2381.70 of 28,020 each year
Answer:

Step-by-step explanation:
Let us consider two points through which the line passes through

Step 1 : <em><u>Find slope of the line</u></em>


Step 2 : <em><u>Find equation of the line.</u></em>
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First of all we must use the same unit measure for all data, otherwise it wouldn't make sense to compare meters and kilometers.
Since one kilometer is the same as 1000 meters, we have that 920000 meters are 920 kilometers.
Now, the train travels at 230 kilometers per hour. It means that it travels 230 kilometers with each passing hour
So, after 1 hour, the train travels 230 km. After two hours, the train travels 2x230 = 460km, and so on
In general, the distance traveled after k hours is
.
We want that distance to be 920, so the equation is

So, the train travels 920 kilometers (i.e. 920000 meters) in 4 hours.