B.16 because 800 divided by 50 is 16
Answer:
17 nickles !
Step-by-step explanation:
First, identify the variables:
n = amount of nickels
d = amount of dimes
Next, setup the equations based on what you know. The first equation is:
n + d = 28
For the second equation, we know that a dime is worth 10¢ and a nickel is 5¢, so it should be:
0.05n + 0.10d = 1.95
This a three-step answer:
In one formula (you can use any of them; most people use the simplest one), single out the variable on one side
Apply the first formula into the second formula, and solve it to get the value of one variable
Apply the answer from the second formula into the first formula, and solve it to get the value of the other variable
======
Step One:
n + d = 28
n + d - d = 28 - d
n = 28 - d
Step Two:
0.05n + 0.10d = 1.95
(0.05 * (28 - d)) + 0.10d = 1.95
1.40 - 0.05d + 0.10d = 1.95
1.40 + 0.05d = 1.95
1.40 - 1.40 + 0.05d = 1.95 - 1.40
0.05d = 0.55
d = 11
Step Three:
n = 28 - d
n = 28 - 11
n = 17
======
Your answer should be 17 nickels and 11 dimes.
You can double check by applying the variables into both formulas.
n + d = 28
17 + 11 = 28
28 = 28
0.05n + 0.10d = 1.95
(0.05 * 17) + (0.10 * 11) = 1.95
0.85 + 1.10 = 1.95
1.95 = 1.95
I hope this helped.
-3.7n - 4 = -11.9
if u want to solve it them add 4 to -11.9 which is -7.9. -7.9 / -3.7 is 2.13513514. (if you wanted to solve it)
Answer:
x = 11
Step-by-step explanation:
Given the expression;
5x+2y=67 ...1
x=3y−7 ....2
Substitute 2 into 1
5(3y-7)+2y = 67
15y - 35 + 2y = 67
17y = 67+35
17y = 102
y = 102/17
y =6
Recall that x = 3y - 7
x = 3(6) - 7
x = 18 - 7
x = 11
Hence the value of x is 11
Answer:
The students can group themselves in 360360 ways
Step-by-step explanation:
For this exercise we need to use the following equation:

This equation give us the number of assignation of n elements in k cell, where n1, n2, ..nk are the element that are in every cell
In this case we have 15 student that need to be assign in three vehicles with an specific capacity. This vehicles would be the equivalent to cells, so we can write the equation as:

Because the first vehicle have 7 seating, the second vehicle have 5 seating and the third vehicle have 3 seating.
Solving the equation we get 360360 ways to organized 15 students in three vehicles with capacity of 7, 5 and 3 seating.