Option C:
x = 6 units
Solution:
QR = 7 units, RS = 5 units, UT = 4 units and ST = x
<em>If two secants intersect outside a circle, the product of the secant segment and its external segment s equal to the product of the other secant segment and its external segment.</em>
⇒ SR × SQ = ST × SU
⇒ 5 × (5 + 7) = x × (x + 4)
⇒ 5 × 12 = x² + 4x
⇒ 60 = x² + 4x
Subtract 60 from both sides.
⇒ 0 = x² + 4x - 60
Switch the sides.
⇒ x² + 4x - 60 = 0
Factor this expression, we get
(x - 6)(x + 10) = 0
x - 6 = 0, x + 10 = 0
x = 6, x = -10
Length cannot be in negative measures.
x = 6 units
Option C is the correct answer.
Answer:
10. answer= 3
Q11 answer = -3
Step-by-step explanation:
Q10.
-3x+9-x+9=3x-3
or, -4x+18=3x-3
or, 3x+4x=18+3
or, 7x=21
or, x=3 <u>answer</u>
<u>Q</u><u>1</u><u>1</u><u>.</u>
1.8-3.7x= -4.2x+0.3
or, 4.2x-3.7x=0.3-1.8
or, 0.5x= -1.5
or, x=-3 <u>answer</u>
More = Addition
"Twice a Number" = Multiplication (specifically by two)
Since the order of operations tell us to multiply before we add, we can simplify
.
I’ll help, but it is difficult to see the terms on the paper!
